The quantity of charge q (Coulomb) passing through a surface of area 5 cm' changing with time as q = 4t3 +5t + 6 (t is in units of seconds). Find the current density at t 4 s. a)J = 8,50 x 104 A/m2 b) J = 1,77 x 10S A/m2 c)J = 2,83 x 10S A/m2 d) J = 3,94 x 10 A/m2 e)J = 5,08 x 105 A/m2 %3D %3D %3D
The quantity of charge q (Coulomb) passing through a surface of area 5 cm' changing with time as q = 4t3 +5t + 6 (t is in units of seconds). Find the current density at t 4 s. a)J = 8,50 x 104 A/m2 b) J = 1,77 x 10S A/m2 c)J = 2,83 x 10S A/m2 d) J = 3,94 x 10 A/m2 e)J = 5,08 x 105 A/m2 %3D %3D %3D
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![The quantity of charge q (Coulomb) passing through a surface of area 5 cm changing
with time as q = 4t + 5t + 6 (t is in units of seconds). Find the current density at
t 4 s.
a) J = 8,50 x 104 A/m2
b) J = 1,77 x 105 A/m2
c)J = 2,83 x 10S A/m2
d) J = 3,94 x 10$ A/m2
e)/ = 5,08 x 10s A/m2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa58e9a2-2edc-45a4-a947-069f0e9cd738%2Ff01c59c8-7d71-41af-89e2-9bf71aa6643e%2F7e3g2c9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The quantity of charge q (Coulomb) passing through a surface of area 5 cm changing
with time as q = 4t + 5t + 6 (t is in units of seconds). Find the current density at
t 4 s.
a) J = 8,50 x 104 A/m2
b) J = 1,77 x 105 A/m2
c)J = 2,83 x 10S A/m2
d) J = 3,94 x 10$ A/m2
e)/ = 5,08 x 10s A/m2
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