An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds. Express your answer in coulombs to two significant figures. Scoresrat AеТextDocument SharingFind the current I through the conductor at time 5.0 seconds.Learning Goal:To learn to apply and combine the concepts of current,current density, and microscopic Ohm's law.Express your answer in amperes to two significant figures.User Settings• View Available Hint(s)An aluminum "12 gauge" wire has a diameter d of 0.205centimeters. The resistivity p of aluminum is2.75 x 10-8 ohm-meters. The electric field in the wirechanges with time asE(t) = 0.0004t² – 0.0001t +0.0004 newtons perCourse ToolsI = 1.2 ASubmitPrevious Answerscoulomb, where time is measured in seconds.CorrectPart BFind the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 sExpress your answer in coulombs to two significant figures.• View Available Hint(s)?Q =CSubmitPrevious Answe rs Request AnswerP PearsonCopyright © 2022 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us |

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.

Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds. Express your answer in coulombs to two significant figures.

Scores
rat A
еТext
Document Sharing
Find the current I through the conductor at time 5.0 seconds.
Learning Goal:
To learn to apply and combine the concepts of current,
current density, and microscopic Ohm's law.
Express your answer in amperes to two significant figures.
User Settings
• View Available Hint(s)
An aluminum "12 gauge" wire has a diameter d of 0.205
centimeters. The resistivity p of aluminum is
2.75 x 10-8 ohm-meters. The electric field in the wire
changes with time as
E(t) = 0.0004t² – 0.0001t +0.0004 newtons per
Course Tools
I = 1.2 A
Submit
Previous Answers
coulomb, where time is measured in seconds.
Correct
Part B
Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 s
Express your answer in coulombs to two significant figures.
• View Available Hint(s)
?
Q =
C
Submit
Previous Answe rs Request Answer
P Pearson
Copyright © 2022 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us |

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Given diameter d of 0.205 cm and resistivity ρ of aluminum is 2.75×10−8 ohm-meters, changes with time as E(t)=0.0004t2−0.0001t+0.0004

We have to find the charge and current.

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