Problem 7A cylindrical platinum wire is 0.0644 mm in diameter and 1.05 m in length. The wirecarries a 1.05 A current. Assume there is one free electron (q = -1.602x10-19 C) perplatinum atom. Avogadro's number is 6.022x1023 atoms per mol. Platinum has a densityof 21.5 g/cm³, a molar mass of 195 g/mol, and a resistivity of 10.6x10-8 Qm.(a) Find the the current density (j), in units of A/m².(b) Find the number density of free electrons (n), in units of m-3.(c) Find the drift velocity of electrons in the wire (va), in units of m/s.(d) Find the magnitude of the electric field in the wire, in units of N/C.(e) Find the potential difference across the wire, in units of Volts.

The diameter of the wire, d=0.0644mm=0.0644×10−3m.So its radius isr=d/2=0.0644×10−32m.So the…

Answered: A cylindrical platinum wire is 0.0644…

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