Answered: The purpose of the following program…

The purpose of the following program is: * #include #include void main () { FILE *p; char c, a; p = fopen ("F:\\data.txt" " r+"); int N=0; do { c = fgetc (p); if ( c==' \n') {cout<>3);

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include<stdio.h> #include<math.h> int main() { char cod; int gal; float cost; printf("Data Codes:"); printf(" \n H-Home \n C-Commercial \n I-Industrial "); printf("\nInput data code: "); scanf("%c", &cod); printf("\nInput number of water (in gallons) used: "); scanf("%d", &gal); if (cod=='H'|| cod=='h') { cost = 250+(0.002*gal); printf("\nTOTAL COST IS %.2f", cost); } else if (cod=='C'||cod=='c') { if (gal<=4000000) { printf("\nTOTAL COST IS 5000.00"); }…
// SumAndProduct.cpp - This program computes sums and products // Input: Interactive// Output: Computed sum and product #include <iostream>#include <string>void sums(int);void products(int);using namespace std; int main() { int number; cout << "Enter a positive integer or 0 to quit: "; cin >> number; while(number != 0) { // Call sums function here // Call products function here cout << "Enter a positive integer or 0 to quit: "; cin >> number; } return 0;} // End of main function// Write sums function here// Write products function here
#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…
Program: #include <stdio.h>#include <string.h>int main() { char s1[100],s2[100]; printf("Enter string1: "); gets(s1); printf("Enter string2: "); gets(s2); int i=strlen(s1); int j=strlen(s2); int count=0; while(count<=j){ s1[i]=s2[count]; count++; i++; } printf("After concatenation = %s",s1); return 0;} Q: Implement the above algorithms using functions in C++
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demo.cpp #include "Poly.h" #include<iostream> using namespace std; int main() { Poly p1; couble d[3]={1,2,3}: Poly p2(3, d); Poly p3(p2); cout << "Polynomial p1 is: "; p1.display(); cout << "Polynomial p2 is: " << p2 << endl; cout << "Polynomial p3 is: " << p3 << endl; if (p2 == p3) { cout << "p2 and p3 are the same."; } else { cout << "p2 and p3 are different."; } cout << endl; cout << "The coefficient of power 1 of p3 is: " << p2.getCoef(1) << endl; p3.setCoef(1, 99); cout << "p3 after setup is: " << p3 << endl; if (p2 == p3) { cout << "p2 and p3 are the same."; } else { cout << "p2 and p3 are different."; } cout << endl; Poly p4; cout << "Please enter the power and coefficients of Polynomial p4: " << endl; cin >> p4; cout <<…
Please fix this code for me, I'm stuck . #include<iostream>#include <iomanip>using namespace std;// the main bodyint main(){std::string item[10],name;int n;float price[10],ST_VAT[10],tax[10],total=0.0,Net;cout<<"Enter the number of items that should be atleast 5 : ";cin>>n;cout<<"Enter the customer's name ";cin>>name;for(int i=1;i<=n;i++){ std::cout<<"\nEnter the item "<<i<<" name , cost, sales tax and VAT :";cin>>name>>price[i]>>ST_VAT[i];tax[i]=price[i]+ST_VAT[i];total=total+tax[i];}Net=total-0.05*total;cout<<swet(5)<<"Food Stuff Grocery Shop"<<endl;cout<<"Customer Name"<<name<<endl;cout<<"ITEM"swet(8)<<"PRICE"<<swet(15)"Sales Tax+ VAT"<<swet(10)<<Sub-Total endl;cout<<SWET(8)<<"------------"<<swet(15)<<"--------------"<<swet(10)<<"----------"endl;for(int…
task7.c Compare 2 strings function cmp will print out > if s1 is "bigger" than s2, < if s1 is "smaller than s2, = if s1 is "equal" to s2. */ #include <stdio.h> #include <string.h> void cmp(char *s1, char *s2){ return; } int main() { char *string1 = "UNIX rules!"; char *string2 = "Windows drools!"; cmp(string1,string2); return 0; } Start with task7.c, implement the cmp() function. The goal of this function is to compare two strings using the sum of the ASCII value of all the characters in each string. Output of your program should look like this: UNIX rules! is smaller than Windows drools!
ê #include using namespace std; int main() { int count = 5; int num = 2; while (count r && num ){ cout << count << " " << num << endl; count -=1; if (count % 2 == 0) num -=1; } return 0; Output: 52 4 1 3 1 20 10
// LargeSmall.cpp - This program calculates the largest and smallest of three integer values. #include <iostream> using namespace std; int main() { // This is the work done in the housekeeping() function // Declare and initialize variables here int largest; // Largest of the three values int smallest; // Smallest of the three values // Prompt the user to enter 3 integer values // Write assignment, add conditional statements here as appropriate // This is the work done in the endOfJob() function // Output largest and smallest number. cout << "The largest value is " << largest << endl; cout << "The smallest value is " << smallest << endl; return 0; }
Write the countDigits function using the following header to count the occurrences of each digit: oid countDigits(const int& number, int dArray[], int size) where size is the size of the dArray array. In this case, it is 10 to store the count of ten digits i.e., from 0 to 9.Write a test program that prompts the user to enter an integer, invokes the countDigits function, and displays the counts of each digit in the given integer.
C++ 2D ARRAY, Continue this codes and change the array to seat[6][6]. Include a loop that asks the user if he wants to try again or no. If the user enters the reserved seat again then display "this seat is taken already". Upon trying again, the reserved seat displayed as (X) must be displayed. My Code: #include <iostream> using namespace std; int main() { cout << "Bus Seats:\n"; cout << "* A B C D\n" << "1 * * * *\n" << "2 * * * *\n" << "3 * * * *\n" << "4 * * * *\n"; char seat[5][5]; int row, column; char col; cout << "Enter the row of your selected seat: "; cin >> row; cout << "Enter the column of your selected seat: "; cin >> col; for(int i=0; i<5; i++){ for(int j=0; j<5; j++){ if(i==0){ switch (j) { case 0: seat[i][j]='*'; break; case 1: seat[i][j]='A'; break; case 2: seat[i][j]='B'; break; case 3: seat[i][j]='C'; break; case 4: seat[i][j]='D'; break; } } else if (j==0) { switch(i) { case 1: seat[i][j]='1';…