Task 2: Command-Line Arguments and String Copying #include #include int main(int argc, char* argv[]) { char str[10]; char *arg1 = argv[1]; int i = 0; int j = 0; while (arg1[i] != '\0') { str[i] = arg1[i]; i++; } while (str[j] != '\0') { printf("%c", str[j]); j++; } return 0; } a. Execute the program with 012345678 as the command-line argument. Observe the output. b. Execute the program with 01. as the command-line argument. Observe the output. Explain what you see and why. c. Execute the program with 01234567890123 as the command-line argument. Observe the output. Explain what you see and why. d. Fix the condition inside the while loop on line 12 to always print the right amount of characters and never read past the end of the str array.
Task 2: Command-Line Arguments and String Copying #include #include int main(int argc, char* argv[]) { char str[10]; char *arg1 = argv[1]; int i = 0; int j = 0; while (arg1[i] != '\0') { str[i] = arg1[i]; i++; } while (str[j] != '\0') { printf("%c", str[j]); j++; } return 0; } a. Execute the program with 012345678 as the command-line argument. Observe the output. b. Execute the program with 01. as the command-line argument. Observe the output. Explain what you see and why. c. Execute the program with 01234567890123 as the command-line argument. Observe the output. Explain what you see and why. d. Fix the condition inside the while loop on line 12 to always print the right amount of characters and never read past the end of the str array.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Task 2: Command-Line Arguments and String Copying
#include <string.h>
#include <stdio.h>
int main(int argc, char* argv[]) {
char str[10];
char *arg1 = argv[1];
int i = 0;
int j = 0;
while (arg1[i] != '\0') {
str[i] = arg1[i];
i++;
}
while (str[j] != '\0') {
printf("%c", str[j]);
j++;
}
return 0;
}
#include <string.h>
#include <stdio.h>
int main(int argc, char* argv[]) {
char str[10];
char *arg1 = argv[1];
int i = 0;
int j = 0;
while (arg1[i] != '\0') {
str[i] = arg1[i];
i++;
}
while (str[j] != '\0') {
printf("%c", str[j]);
j++;
}
return 0;
}
a. Execute the program with 012345678 as the command-line argument. Observe the output.
b. Execute the program with 01. as the command-line argument. Observe the output. Explain what you see and
why.
c. Execute the program with 01234567890123 as the command-line argument. Observe the output. Explain
what you see and why.
d. Fix the condition inside the while loop on line 12 to always print the right amount of characters and never
read past the end of the str array.
b. Execute the program with 01. as the command-line argument. Observe the output. Explain what you see and
why.
c. Execute the program with 01234567890123 as the command-line argument. Observe the output. Explain
what you see and why.
d. Fix the condition inside the while loop on line 12 to always print the right amount of characters and never
read past the end of the str array.
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