The probability distribution shows the number of items a customer buys in a book store and their corresponding probabilities. Find the mean of this distribution. 1 0..60 0.28 0.07 0.03 0.02 2 3 4 5 P(X) Select the correct response: 0.90 0.9 1.59 2.61
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- Example: Finding the Mean, Variance, and Standard Deviation The table describes the probability distribution for the number children in homeschool families in North Bay. Find the mean, variance, and standard deviation for this probability distribution. x: number of children 0 1 2 3 4 5 6 Total P(x) 0 1/11 ≈ 0.09 4/11≈ 0.36 2/11 ≈ 0.18 2/11≈ 0.18 1/11≈ 0.09 1/11 ≈ 0.09 1X P(x) 0.2 1 0.3 2 0.05 3 0.45 Find the mean of this probability distribution. Round your answer to one decimal place.Assume the geometric distribution applies. Use the given probability of success p to find the indicated probability. Find P(5) when p= 0.90
- Hour: 1. Let Y the number of siblings for a student at a local high school. Suppose we choose someone from the school at random. The probability distribution of Y is as Name: Date: follows. Y 2. 3. 4 5+ Probability 0.02 0.25 0.35 0.20 0.10 0.08 (a) Is Y a discrete or continuous? Explain. (b) Is this a valid probability distribution? Explain. (c) Create a histogram for the probability distribution and describe its shape. (d) Find the probability that the randomly selected student has at least one sibling. (e) Describe in words what P(Y>2) means and find the probability. (f) Calculate the mean of Y. Interpret this in context. (g) The standard deviation is 1.236. Interpret this in context. © 2017 BFW Publishers Starnes/Tabor Statistics and Probability with Applications 3/eThe following is the probability distribution for an athlete of winning medals. Medal (Event) Gold E1 Silver E2 Bronze E3 No medal E4 P(Ei) 0.10 0.15 0.20 0.55 Find the probability of earning a medal. Group of answer choices 0.45 0.9 0.15 0.75 0.25The table below is to be valid probability distribution for a data set. x P(x) 3 0.07 4 0.38 5 0.44 6 0.07 12 What is the missing probability to complete the probability distribution? P(12) =
- Determine whether this table represents a probability distribution.PavnThe accompanying table lists the outcomes and the probability distribution for a student renting videos during the week while on campus. Video Rentals per Week during Semester Outcome (number of O weekly video rentals) Probability distribution Outcome 0 (number of weekly video rentals) Probability distribution 1 0 69.81 2 Write the cumulative probability distribution in the table below. Use two decimal places. 3 1.81 4 0.05 0.55 0.25 0.05 0.07 0.02 0.01 Hint: Write your answers in two decimal places. 5 8 The probability of renting between two and four videos a week is 126.95 60 57.14 5 25 600 and the probability of renting less than three a week is
- Use the probability distribution to complete parts (a) and (b) below. Activities Probability0 0.0591 0.1212 0.1633 0.1794 0.2165 0.1276 0.0837 0.052 The number of school-related extracurricular activities per student (a) Find the mean, variance, and standard deviation of the probability distribution. (b) Interpret the results.Write the binomial probability and the normal probability for the shaded region of the graph. Find the value of each probability and compare the results. AP(x) 0.24- n = 16 p= 0.5 0.2- 0.16- 0.12- 0.08- 0.04- 0- 2 4 6 8 10 12 14 16 Write the binomial probability for the shaded region of the graph and find its value. Select the correct choice below and fill in the answer box within your choice. (Round to four decimal places as needed.) O A. P(4K The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions. Complete parts (a) through (c) below. Click the icon to view the data for fatal crashes in 2016. (a) Among fatal crashes in unknown weather conditions, what is the probability that a randomly selected fatal crash occurs when it is dawn/dusk? The probability that a randomly selected fatal crash in unknown weather conditions occurs when it is dawn/dusk is approximately. (Round to three decimal places as needed.) Data table Weather Daylight Dark, but Lighted 5875 497 51 54 255 Normal Rain Snow/Sleet Other Unknown 14,307 875 219 125 810 (...) Dark 8151 681 156 220 548 Dawn/Dusk Other 1183 87 40 71 65 8 2 9 133 X