Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students X 0 1 34 P(x) 0.3 0.26 0.16 0.09 ? A. 0.44 OB. -0.75 C. 0.81 D. 0.19 2

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**Probability Distribution Exercise:**

Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given below in the table:

| x   | 0   | 1   | 2   | 3   | 4   |
|-----|-----|-----|-----|-----|-----|
| P(x)| 0.3 | 0.26| 0.16| 0.09| ?   |

To find the missing value in a probability distribution, the sum of all probabilities must equal 1.

**Options:**

- A. 0.44
- B. -0.75
- C. 0.81
- D. 0.19

**Explanation:**

1. Add all the given probabilities: \(0.3 + 0.26 + 0.16 + 0.09 = 0.81\).
2. Subtract the sum from 1 to find the missing probability: \(1 - 0.81 = 0.19\).

The correct answer is option D: 0.19.
Transcribed Image Text:**Probability Distribution Exercise:** Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given below in the table: | x | 0 | 1 | 2 | 3 | 4 | |-----|-----|-----|-----|-----|-----| | P(x)| 0.3 | 0.26| 0.16| 0.09| ? | To find the missing value in a probability distribution, the sum of all probabilities must equal 1. **Options:** - A. 0.44 - B. -0.75 - C. 0.81 - D. 0.19 **Explanation:** 1. Add all the given probabilities: \(0.3 + 0.26 + 0.16 + 0.09 = 0.81\). 2. Subtract the sum from 1 to find the missing probability: \(1 - 0.81 = 0.19\). The correct answer is option D: 0.19.
Expert Solution
Step 1
x P(x)
0 0.3
1 0.26
2 0.16
3 0.09
4 ?

 

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