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Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students 0. 1 4 4 1 3 P(x) 11 11 22 22 O A. 11 8 O B. 11 о С. 22 O D. 11

Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students 0. 1 4 4 1 3 P(x) 11 11 22 22 O A. 11 8 O B. 11 о С. 22 O D. 11

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Title: Determining Missing Values in a Probability Distribution** **Introduction:** In this exercise, we will learn how to find the missing value in a probability distribution. The probability distribution given represents the likelihood of a tutor seeing a certain number of students. **Problem Statement:** Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given. **Probability Distribution Table:** | x | 0 | 1 | 2 | 3 | 4 | |-----|-----|-----|-----|-----|-----| | P(x)| 3/11| 4/11| 1/22| ? | 5/22| **Options:** - A. \(-\frac{5}{11}\) - B. \(\frac{8}{11}\) - C. \(\frac{3}{22}\) - D. \(\frac{1}{11}\) **Explanation:** To find the missing probability, we need to ensure that the sum of all probabilities equals 1. We add the given probabilities and solve for the missing value. **Conclusion:** Choose the correct option from the choices above to complete the probability distribution.
Transcribed Image Text:**Title: Determining Missing Values in a Probability Distribution** **Introduction:** In this exercise, we will learn how to find the missing value in a probability distribution. The probability distribution given represents the likelihood of a tutor seeing a certain number of students. **Problem Statement:** Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given. **Probability Distribution Table:** | x | 0 | 1 | 2 | 3 | 4 | |-----|-----|-----|-----|-----|-----| | P(x)| 3/11| 4/11| 1/22| ? | 5/22| **Options:** - A. \(-\frac{5}{11}\) - B. \(\frac{8}{11}\) - C. \(\frac{3}{22}\) - D. \(\frac{1}{11}\) **Explanation:** To find the missing probability, we need to ensure that the sum of all probabilities equals 1. We add the given probabilities and solve for the missing value. **Conclusion:** Choose the correct option from the choices above to complete the probability distribution.
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