Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students 0 1 P(x) 0.45 0.02 0.06 X A. -0.93 OB. 0.54 OC. 0.46 OD. 0.53 2 3 4 0.01 2

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**Probability Distribution Problem**

Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given in the table below.

| x   | 0    | 1    | 2    | 3    | 4   |
|-----|------|------|------|------|-----|
| P(x)| 0.45 | 0.02 | 0.06 | 0.01 | ?   |

To find the missing probability value for x = 4, ensure that the sum of all probabilities equals 1, since the sum of probabilities in a distribution must always equal 1.

\[ P(0) + P(1) + P(2) + P(3) + P(4) = 1 \]

\[ 0.45 + 0.02 + 0.06 + 0.01 + ? = 1 \]

Solve \[ ? = 1 - (0.45 + 0.02 + 0.06 + 0.01) \]

**Answer Choices:**

A. 0.93  
B. 0.54  
C. 0.46  
D. 0.53  

To calculate the missing value, subtract the sum of the given probabilities from 1.
Transcribed Image Text:**Probability Distribution Problem** Determine the probability distribution's missing value. The probability that a tutor will see 0, 1, 2, 3, or 4 students is given in the table below. | x | 0 | 1 | 2 | 3 | 4 | |-----|------|------|------|------|-----| | P(x)| 0.45 | 0.02 | 0.06 | 0.01 | ? | To find the missing probability value for x = 4, ensure that the sum of all probabilities equals 1, since the sum of probabilities in a distribution must always equal 1. \[ P(0) + P(1) + P(2) + P(3) + P(4) = 1 \] \[ 0.45 + 0.02 + 0.06 + 0.01 + ? = 1 \] Solve \[ ? = 1 - (0.45 + 0.02 + 0.06 + 0.01) \] **Answer Choices:** A. 0.93 B. 0.54 C. 0.46 D. 0.53 To calculate the missing value, subtract the sum of the given probabilities from 1.
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