The previous step focused on friction for horizontal surfaces. As we discussed above, angled surfaces like the wedge below have different considerations. FN = mg cos(0) F₁ = mg 0 What is the coefficient of static friction ? Fx = ? F₁=? Fy=mg cos(0) Specifically, we have the following considerations. 1. The normal force is not equal to mg. 2. There is a force acting along the angle of the wedge due to gravity. Fx = mg sin(0) Let's consider the implications of this type of problem with the following examples. For all of the examples, the box has a mass of 25 kg. Imagine the box is on a surface that allows you to adjust the incline angle, 0. You find the maximum angle where the box remains stationary. That is, at any higher angle, and the box begins to slide. The static friction force at this maximum angle is 150 N. What is the angle 0 (in degrees)? Now you raise the incline to an angle of 60° greater than the angle of maximum static friction found above. At this angle, the box slides down as soon as it is set on the plane. When the box is in motion, you find that starting from rest, it slides 10 meters in 2.0 seconds. What is the coefficient of kinetic friction between the box and wedge?

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The previous step focused on friction for horizontal surfaces. As we discussed above, angled surfaces like the wedge below
have different considerations.
FN = mg cos(0)
F₁ = mg
F₁
= ?
F₁ = ?
Fy=mg cos(0)
Specifically, we have the following considerations.
1. The normal force is not equal to mg.
2. There is a force acting along the angle of the wedge due to gravity.
What is the coefficient of static friction ?
Fx = mg sin(0)
Let's consider the implications of this type of problem with the following examples. For all of the examples, the box has a
mass of 25 kg.
Imagine the box is on a surface that allows you to adjust the incline angle, 0. You find the maximum angle where the box
remains stationary. That is, at any higher angle, and the box begins to slide. The static friction force at this maximum angle
is 150 N. What is the angle 0 (in degrees)?
Now you raise the incline to an angle of 60° greater than the angle of maximum static friction found above. At this angle,
the box slides down as soon as it is set on the plane. When the box is in motion, you find that starting from rest, it slides
10 meters in 2.0 seconds. What is the coefficient of kinetic friction between the box and wedge?
Transcribed Image Text:The previous step focused on friction for horizontal surfaces. As we discussed above, angled surfaces like the wedge below have different considerations. FN = mg cos(0) F₁ = mg F₁ = ? F₁ = ? Fy=mg cos(0) Specifically, we have the following considerations. 1. The normal force is not equal to mg. 2. There is a force acting along the angle of the wedge due to gravity. What is the coefficient of static friction ? Fx = mg sin(0) Let's consider the implications of this type of problem with the following examples. For all of the examples, the box has a mass of 25 kg. Imagine the box is on a surface that allows you to adjust the incline angle, 0. You find the maximum angle where the box remains stationary. That is, at any higher angle, and the box begins to slide. The static friction force at this maximum angle is 150 N. What is the angle 0 (in degrees)? Now you raise the incline to an angle of 60° greater than the angle of maximum static friction found above. At this angle, the box slides down as soon as it is set on the plane. When the box is in motion, you find that starting from rest, it slides 10 meters in 2.0 seconds. What is the coefficient of kinetic friction between the box and wedge?
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