The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCH3CO₂ is a weak acid. 0.9 mol of NaOH is added to 1.0 L of a 0.9M HCH₂CO₂ 0 solution. 0.3 mol of NaOH is added to 1.0 L of a solution that is 0.8M in both HCH₂CO₂ and NaCH3CO2. U 0 O acids: bases: other: acids: bases: other: 0 X S

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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major
species present at equilibrium. You can leave out water itself.
Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the
'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row.
You will find it useful to keep in mind that HCH3CO₂ is a weak acid.
0.9 mol of NaOH is added to
1.0 L of a 0.9M HCH₂ CO₂
solution.
0.3 mol of NaOH is added to
1.0 L of a solution that is
0.8M in both HCH, CO₂
2
and NaCH3CO₂.
0
acids:
bases:
other:
acids: 0
bases:
other:
2
X
0,0,...
S
Transcribed Image Text:The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCH3CO₂ is a weak acid. 0.9 mol of NaOH is added to 1.0 L of a 0.9M HCH₂ CO₂ solution. 0.3 mol of NaOH is added to 1.0 L of a solution that is 0.8M in both HCH, CO₂ 2 and NaCH3CO₂. 0 acids: bases: other: acids: 0 bases: other: 2 X 0,0,... S
Expert Solution
Step 1

Given -

1.Moles of NaOH = 0.9 mol

  Volume of HCH3CO2 =1.0 L

  Molarity of HCH3CO2 = 0.9M

2. Moles of NaOH = 0.3 mol

   Volume of solution = 1.0L

   Molarity of solution = 0.8M

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