Can you please help me with this question? Thank you so much! Appreciate your help! ### Motion Along an x-axisThe position of an object moving along an x-axis is given by the function:\[ x = 3.09t - 4.24t^2 + 1.05t^3 \]Where:- \( x \) is the position in meters (m)- \( t \) is the time in seconds (s)#### Problems:1. **Determine the position of the object at the following values of \( t \):** - (a) \( t = 1 \text{ s} \) - (b) \( t = 2 \text{ s} \) - (c) \( t = 3 \text{ s} \) - (d) \( t = 4 \text{ s} \) 2. **Additional Questions:** - (e) What is the object's displacement between \( t = 0 \) s and \( t = 4 \) s? - (f) What is its average velocity from \( t = 2 \) s to \( t = 4 \) s?#### Answer Form:(a) Position at 1 second: \( x \) = [Text box for numerical input] [Dropdown menu for units](b) Position at 2 seconds: \( x \) = [Text box for numerical input] [Dropdown menu for units](c) Position at 3 seconds: \( x \) = [Text box for numerical input] [Dropdown menu for units](d) Position at 4 seconds: \( x \) = [Text box for numerical input] [Dropdown menu for units](e) Displacement between \( t = 0 \) s and \( t = 4 \) s: \( \Delta x \) = [Text box for numerical input] [Dropdown menu for units](f) Average velocity from \( t = 2 \) s to \( t = 4 \) s: \( \bar{v} \) = [Text box for numerical input] [Dropdown menu for units]**Note:**For (a), (b), (c), and (d), calculate the position by substituting the corresponding value of \( t \) into the equation given. For (e), find the difference in position \( x \) at \( t = 4 \) s and \( x \) at \( t = 0 \

Name: Can you please help me with this question? Thank you so much! Apprecia
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Can you please help me with this question? Thank you so much! Appreciate your help! ### Motion Along an x-axisThe position of an object moving along an x-axis is given by the function:\[ x = 3.09t - 4.24t^2 + 1.05t^3 \]Where:- \( x \) is the position