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A wire having a mass per unit length of 1.5 g/cm carries a current of 15 A to the east. What are the magnitude and direction of the minimum magnetic field that will levitate the wire vertically? .15 s /m

A wire having a mass per unit length of 1.5 g/cm carries a current of 15 A to the east. What are the magnitude and direction of the minimum magnetic field that will levitate the wire vertically? .15 s /m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Description:** A wire having a mass per unit length of 1.5 g/cm carries a current of 15 A to the east. What are the magnitude and direction of the minimum magnetic field that will levitate the wire vertically? **Solution Steps and Annotations:** 1. The mass per unit length of the wire is given as: - \(1.5 \, \text{g/cm}\) 2. The current flowing through the wire is: - \(15 \, \text{A}\) 3. To solve the problem, identify the magnitude and direction: - The necessary magnitude of the magnetic field is: - \(0.056 \, \text{T}\) - The direction of this magnetic field should be: - South These handwritten annotations help in deriving the required magnetic field's characteristics to achieve vertical levitation of the wire.
Transcribed Image Text:**Problem Description:** A wire having a mass per unit length of 1.5 g/cm carries a current of 15 A to the east. What are the magnitude and direction of the minimum magnetic field that will levitate the wire vertically? **Solution Steps and Annotations:** 1. The mass per unit length of the wire is given as: - \(1.5 \, \text{g/cm}\) 2. The current flowing through the wire is: - \(15 \, \text{A}\) 3. To solve the problem, identify the magnitude and direction: - The necessary magnitude of the magnetic field is: - \(0.056 \, \text{T}\) - The direction of this magnetic field should be: - South These handwritten annotations help in deriving the required magnetic field's characteristics to achieve vertical levitation of the wire.
Expert Solution
Step 1

The given values are,

mL=1.5 g/cm=1.5 g/cm10-3 kg1 g1 cm10-2 m=0.15 kg/mI=15 A

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