A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k. After suspending a mass of 335.0 g from the spring, the student notices the spring is displaced 25.5 cm from its previous equilibrium. With this information, calculate the spring constant. spring constant: N/m When the spring, with the attached 335.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate the period of oscillation, T, neglecting the mass of the spring itself. T =
A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k. After suspending a mass of 335.0 g from the spring, the student notices the spring is displaced 25.5 cm from its previous equilibrium. With this information, calculate the spring constant. spring constant: N/m When the spring, with the attached 335.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate the period of oscillation, T, neglecting the mass of the spring itself. T =
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Transcribed Image Text:?
A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal
support. The student is asked to find the spring constant, k. After suspending a mass of 335.0 g from the spring, the student
notices the spring is displaced 25.5 cm from its previous equilibrium. With this information, calculate the spring constant.
spring constant:
When the spring, with the attached 335.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate
the period of oscillation, T, neglecting the mass of the spring itself.
T=
Displacement (cm) from equilibrium
N/m
In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously.
The student pulls the mass down an additional 19.1 cm from the equilibrium point of 25.5 cm when the mass is stationary and
allows the system to oscillate. Using the equilibrium point of 25.5 cm as the zero point for total potential energy, calculate the
velocity and total potential energy for each displacement given and insert the correct answer.
velocity THI/ST
Total Dotentral energy (J)
S
Transcribed Image Text:?
In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously.
The student pulls the mass down an additional 19.1 cm from the equilibrium point of 25.5 cm when the mass is stationary and
allows the system to oscillate. Using the equilibrium point of 25.5 cm as the zero point for total potential energy, calculate the
velocity and total potential energy for each displacement given and insert the correct answer.
Displacement (cm) from equilibrium
19.1
14.0
1.19
0.236
Velocity (m/s)
Answer Bank
0.127
0
M
#
M
M
M
H
0.806
Total potential energy (J)
2
0.419
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