The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a b dn = 1₂ Icr = M B Aso Cross section Asc Ast N.A. Ast Stress profile (concrete) Cross section before cracking Q2) Now, the live load increases gradually and the moment at the critical section just exceeds the cracking moment (Mcr), but the compressive section of the concrete is still under the linear elastic region. Please be reminded that in the flexural design, the crack of the concrete section starts where the tensile stress reaches the tensile strength. It is assumed that the cracks then propagate rapidly up to the entire tension section (up to the neutral axis) and this cracked concrete section cannot resist the tension. It should be noted that in reality, concrete sections between the primary cracks can still resist some tensile stresses as shown in the figure, which should be considered in the displacement design. However, in flexure design, we design the critical section where the largest moment occurs and thus it is reasonable to have such a primary crack in this critical section. 2.1 Find the new neutral axis in the cracked section under the elastic region on the compressive section and also find the cracked second moment of areas (Icr). The transformed area method (dn = Σyi A₁/A₂) is still valid. However, we may need to solve the quadratic equation for calculating the neutral axis distance from the top surface. J 1₂ secondary crack W mm C (centre) f' = 38 Mpa f'ctf = 3.5 MPa fsy = 500 MPa E, = 200 GPa E = 28600 MPa 10⁹ mm¹ a D + b a Neutral axis primary cracks 4₂ A N.A → cracks Ast Cross section just after cracking $ Stress profile (concrete) M → -concrete in tension O Variables 1₁2.5 m 1₂3m a b с ASC Ast 55 mm 600 mm 400 mm 620 mm² 3200 mm² E
The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a b dn = 1₂ Icr = M B Aso Cross section Asc Ast N.A. Ast Stress profile (concrete) Cross section before cracking Q2) Now, the live load increases gradually and the moment at the critical section just exceeds the cracking moment (Mcr), but the compressive section of the concrete is still under the linear elastic region. Please be reminded that in the flexural design, the crack of the concrete section starts where the tensile stress reaches the tensile strength. It is assumed that the cracks then propagate rapidly up to the entire tension section (up to the neutral axis) and this cracked concrete section cannot resist the tension. It should be noted that in reality, concrete sections between the primary cracks can still resist some tensile stresses as shown in the figure, which should be considered in the displacement design. However, in flexure design, we design the critical section where the largest moment occurs and thus it is reasonable to have such a primary crack in this critical section. 2.1 Find the new neutral axis in the cracked section under the elastic region on the compressive section and also find the cracked second moment of areas (Icr). The transformed area method (dn = Σyi A₁/A₂) is still valid. However, we may need to solve the quadratic equation for calculating the neutral axis distance from the top surface. J 1₂ secondary crack W mm C (centre) f' = 38 Mpa f'ctf = 3.5 MPa fsy = 500 MPa E, = 200 GPa E = 28600 MPa 10⁹ mm¹ a D + b a Neutral axis primary cracks 4₂ A N.A → cracks Ast Cross section just after cracking $ Stress profile (concrete) M → -concrete in tension O Variables 1₁2.5 m 1₂3m a b с ASC Ast 55 mm 600 mm 400 mm 620 mm² 3200 mm² E
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter12: Composite Materials
Section: Chapter Questions
Problem 12.7P: Estimate the transverse tensile strength of the concrete in Problem 12.6.
Related questions
Question
100%
Please do the questions 2.2 and 2.3
i will be very very appreciate!!!!
In question 2.1:dn=215.4 mm
Icr=2664863900 mm4
![The point loads are placed at the fixed positions shown in the figure and they are
live loads.
A
k
a
b
a
b
dn =
1₂
Icr=
M
B
7
Ast
Stress profile (concrete)
Cross section before cracking
Aso
Cross section
Asc
Ast
N.A.
Q2) Now, the live load increases gradually and the moment at the critical section just exceeds
the cracking moment (Mcr), but the compressive section of the concrete is still under the linear
elastic region. Please be reminded that in the flexural design, the crack of the concrete section
starts where the tensile stress reaches the tensile strength. It is assumed that the cracks then
propagate rapidly up to the entire tension section (up to the neutral axis) and this cracked
concrete section cannot resist the tension. It should be noted that in reality, concrete sections
between the primary cracks can still resist some tensile stresses as shown in the figure, which
should be considered in the displacement design. However, in flexure design, we design the
critical section where the largest moment occurs and thus it is reasonable to have such a
primary crack in this critical section.
2.1 Find the new neutral axis in the cracked section under the elastic region on the
compressive section and also find the cracked second moment of areas (Icr). The
transformed area method (dn = Σyi A₁/A₂) is still valid. However, we may
need to solve the quadratic equation for calculating the neutral axis distance from
the top surface.
1₂
secondary
crack
W
mm
C (centre)
f' = 38 Mpa
f'ctf = 3.5 MPa
fsy = 500 MPa
E, = 200 GPa
E = 28600 MPa
x 10⁹ mm¹
a
D
+
b
a
Neutral axis
primary
cracks
4₂
A
N.A
→ cracks
Ast
Cross section just after cracking
$
Stress profile (concrete)
M
→
-concrete in tension
O
Variables
1₁2.5 m
1₂3m
a
b
с
ASC
Ast
55 mm
600
mm
400
mm
620
mm²
3200
mm²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa482f51c-60d4-424a-a66b-e3f21758d1f0%2Fec020088-2d42-42b6-9cc1-c4fed1fb23a0%2Fqvj0r9n_processed.png&w=3840&q=75)
Transcribed Image Text:The point loads are placed at the fixed positions shown in the figure and they are
live loads.
A
k
a
b
a
b
dn =
1₂
Icr=
M
B
7
Ast
Stress profile (concrete)
Cross section before cracking
Aso
Cross section
Asc
Ast
N.A.
Q2) Now, the live load increases gradually and the moment at the critical section just exceeds
the cracking moment (Mcr), but the compressive section of the concrete is still under the linear
elastic region. Please be reminded that in the flexural design, the crack of the concrete section
starts where the tensile stress reaches the tensile strength. It is assumed that the cracks then
propagate rapidly up to the entire tension section (up to the neutral axis) and this cracked
concrete section cannot resist the tension. It should be noted that in reality, concrete sections
between the primary cracks can still resist some tensile stresses as shown in the figure, which
should be considered in the displacement design. However, in flexure design, we design the
critical section where the largest moment occurs and thus it is reasonable to have such a
primary crack in this critical section.
2.1 Find the new neutral axis in the cracked section under the elastic region on the
compressive section and also find the cracked second moment of areas (Icr). The
transformed area method (dn = Σyi A₁/A₂) is still valid. However, we may
need to solve the quadratic equation for calculating the neutral axis distance from
the top surface.
1₂
secondary
crack
W
mm
C (centre)
f' = 38 Mpa
f'ctf = 3.5 MPa
fsy = 500 MPa
E, = 200 GPa
E = 28600 MPa
x 10⁹ mm¹
a
D
+
b
a
Neutral axis
primary
cracks
4₂
A
N.A
→ cracks
Ast
Cross section just after cracking
$
Stress profile (concrete)
M
→
-concrete in tension
O
Variables
1₁2.5 m
1₂3m
a
b
с
ASC
Ast
55 mm
600
mm
400
mm
620
mm²
3200
mm²
![2.2 The applied loads keep increasing and the concrete section is now under the non-linear
regime. The neutral axis moves upward and the concrete compressive section has the
curvilinear distribution of concrete stresses, which require the integration of the stress to
compute the neutral axis and the ultimate nominal moment. To avoid the complex calculation,
the Whitney stress block is introduced during the class. It should be noted that this ultimate
strength stage is a condition of the flexural design. Thus, when we design the beam in terms of
bending, we can only consider this ultimate condition directly without the previous linear
stage.
Find the neutral axis distance from the top fibre (dn) at the ultimate strength stage and the
ultimate nominal moment (Mu) that this concrete section can carry using the given section
dimensions and materials properties.
b
NA.
Ag
Stress profile (concrete)
Cross section before cracking
a
dn =
M₂=
A
M* =
b
Stress profile (concrete)
Cross section just after cracking
(No answer given) +
(No answer given)
No
Yes
N.A
→ cracks
mm
kNm
kNm
2.3 The beam now has to carry an unfactored dead load (including self-weight) of G = 10
kN/m and an unfactored live load of Q = 20 kN/m. Two concentrated unfactored live
loads of P = 15 kN are applied at the positions shown in the figure. Determine if the design
moment strength (Mu) exceeds the factored design moment M. p = 0.85
Does the beam satisfy the design requirement?
b
Note: In flexural design, the ultimate moment in the section occurs when the
compressive fibre reached the ultimate concrete strain (&cu = 0.003). The nominal
ultimate moment is computed from the property of the concrete section and
independent to the applied loads.
cracks
At
Cross section non-linear
Stress profile (concrete)
U](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa482f51c-60d4-424a-a66b-e3f21758d1f0%2Fec020088-2d42-42b6-9cc1-c4fed1fb23a0%2Fncki2tr_processed.png&w=3840&q=75)
Transcribed Image Text:2.2 The applied loads keep increasing and the concrete section is now under the non-linear
regime. The neutral axis moves upward and the concrete compressive section has the
curvilinear distribution of concrete stresses, which require the integration of the stress to
compute the neutral axis and the ultimate nominal moment. To avoid the complex calculation,
the Whitney stress block is introduced during the class. It should be noted that this ultimate
strength stage is a condition of the flexural design. Thus, when we design the beam in terms of
bending, we can only consider this ultimate condition directly without the previous linear
stage.
Find the neutral axis distance from the top fibre (dn) at the ultimate strength stage and the
ultimate nominal moment (Mu) that this concrete section can carry using the given section
dimensions and materials properties.
b
NA.
Ag
Stress profile (concrete)
Cross section before cracking
a
dn =
M₂=
A
M* =
b
Stress profile (concrete)
Cross section just after cracking
(No answer given) +
(No answer given)
No
Yes
N.A
→ cracks
mm
kNm
kNm
2.3 The beam now has to carry an unfactored dead load (including self-weight) of G = 10
kN/m and an unfactored live load of Q = 20 kN/m. Two concentrated unfactored live
loads of P = 15 kN are applied at the positions shown in the figure. Determine if the design
moment strength (Mu) exceeds the factored design moment M. p = 0.85
Does the beam satisfy the design requirement?
b
Note: In flexural design, the ultimate moment in the section occurs when the
compressive fibre reached the ultimate concrete strain (&cu = 0.003). The nominal
ultimate moment is computed from the property of the concrete section and
independent to the applied loads.
cracks
At
Cross section non-linear
Stress profile (concrete)
U
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