The pipe elbow below discharges water at rate of SN/100 (m/s) into the atmosphere at section 2 (where SN is the sum of your student number). The total volume of the passage between section 1 and 2 is equal to 0.2 m and the total mass of the elbow material between section 1 and 2 is equal to 10 x SN (kg). Neglect any friction losses. Calculate the horizontal and vertical forces acting on the elbow. Also calculate the resultant force and angle of force on the elbow. Section (1) D; = 0.4m 135° 0.5m Datum Section (2) D2 = 0.2m
The pipe elbow below discharges water at rate of SN/100 (m/s) into the atmosphere at section 2 (where SN is the sum of your student number). The total volume of the passage between section 1 and 2 is equal to 0.2 m and the total mass of the elbow material between section 1 and 2 is equal to 10 x SN (kg). Neglect any friction losses. Calculate the horizontal and vertical forces acting on the elbow. Also calculate the resultant force and angle of force on the elbow. Section (1) D; = 0.4m 135° 0.5m Datum Section (2) D2 = 0.2m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The pipe elbow below discharges water at rate of SN/100 (m3/s) into the atmosphere at section 2. The total volume of the passage between sections 1 and 2 is equal to 0.2 m3 and the total mass of the elbow material between sections 1 and 2 is equal to 10 x SN (kg). Neglect any friction losses.
Calculate the horizontal and vertical forces acting on the elbow. Also, calculate the resultant force and angle of force on the elbow.
****SN=21
![FORMULA SHEET
Q = V*A
P V?
pg 2g
+ Z1
2 +2+ Z2 + h, + hm
pg 2g
F = PxA
EF, = pQ(V2x – V1x)
EF, = pQ(V2y - Vay)
%3D
FR = Fåx + Fhy
FRY
$ = tan
FRX](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8b86369-76b8-4435-a6f1-bb8d0568ca99%2F820fbed6-0105-4822-9898-bedca28b4fed%2Fkdbpwhp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:FORMULA SHEET
Q = V*A
P V?
pg 2g
+ Z1
2 +2+ Z2 + h, + hm
pg 2g
F = PxA
EF, = pQ(V2x – V1x)
EF, = pQ(V2y - Vay)
%3D
FR = Fåx + Fhy
FRY
$ = tan
FRX
![The pipe elbow below discharges water at rate of SN/100 (m³/s) into the atmosphere at section 2
(where SN is the sum of your student number). The total volume of the passage between section
1 and 2 is equal to 0.2 m³ and the total mass of the elbow material between section 1 and 2 is
equal to 10 x SN (kg). Neglect any friction losses.
Calculate the horizontal and vertical forces acting on the elbow. Also calculate the resultant force
and angle of force on the elbow.
Section
(1) D; = 0.4m
135°
0.5m
Datum
Section
(2)
D2 = 0.2m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8b86369-76b8-4435-a6f1-bb8d0568ca99%2F820fbed6-0105-4822-9898-bedca28b4fed%2F8p8p8io_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The pipe elbow below discharges water at rate of SN/100 (m³/s) into the atmosphere at section 2
(where SN is the sum of your student number). The total volume of the passage between section
1 and 2 is equal to 0.2 m³ and the total mass of the elbow material between section 1 and 2 is
equal to 10 x SN (kg). Neglect any friction losses.
Calculate the horizontal and vertical forces acting on the elbow. Also calculate the resultant force
and angle of force on the elbow.
Section
(1) D; = 0.4m
135°
0.5m
Datum
Section
(2)
D2 = 0.2m
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