The picture below shows a pool you filled with 100.00 L of water along with a 13.50 kg aluminum block. Then, you drop this aluminum block into the pool so the volume rises to 105.00 L. What is the volume of the block? 105.00 1 O 5.00 L O 105.00 L O Depends on block shape O Not enough information provided

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### Understanding Volume Displacement

The image presents a problem involving the concept of volume displacement. 

#### Problem Statement
The picture below shows a pool filled with 100.00 L of water along with a 13.50 kg aluminum block. When the aluminum block is dropped into the pool, the volume of the water rises to 105.00 L. The task is to determine the volume of the aluminum block.

#### Visual Explanation
The problem includes two illustrated states of a pool:
1. **Initial State**: The pool is filled with 100.00 liters of water, depicted in a graphic with a labeled water level.
2. **Final State**: After adding the aluminum block, the water level rises to 105.00 liters. This increment in water level is also represented graphically.

#### Answer Choices
The multiple-choice question provided has four options to select from:
- 5.00 L
- 105.00 L
- Depends on block shape
- Not enough information provided

### Solution
The volume of the aluminum block can be determined by the difference in the water levels before and after the block is introduced into the pool.

- **Initial Volume of Water**: 100.00 L
- **Final Volume of Water**: 105.00 L

#### Calculation
The volume displaced by the block is:

\[ \text{Volume displaced} = \text{Final Volume} - \text{Initial Volume} \]
\[ = 105.00 \, \text{L} - 100.00 \, \text{L} \]
\[ = 5.00 \, \text{L} \]

Thus, the volume of the aluminum block is 5.00 liters.

### Correct Answer
- **5.00 L**

This solution illustrates the principle of volume displacement, where the submersion of an object in a fluid increases the fluid's apparent volume by an amount equal to the volume of the object.
Transcribed Image Text:### Understanding Volume Displacement The image presents a problem involving the concept of volume displacement. #### Problem Statement The picture below shows a pool filled with 100.00 L of water along with a 13.50 kg aluminum block. When the aluminum block is dropped into the pool, the volume of the water rises to 105.00 L. The task is to determine the volume of the aluminum block. #### Visual Explanation The problem includes two illustrated states of a pool: 1. **Initial State**: The pool is filled with 100.00 liters of water, depicted in a graphic with a labeled water level. 2. **Final State**: After adding the aluminum block, the water level rises to 105.00 liters. This increment in water level is also represented graphically. #### Answer Choices The multiple-choice question provided has four options to select from: - 5.00 L - 105.00 L - Depends on block shape - Not enough information provided ### Solution The volume of the aluminum block can be determined by the difference in the water levels before and after the block is introduced into the pool. - **Initial Volume of Water**: 100.00 L - **Final Volume of Water**: 105.00 L #### Calculation The volume displaced by the block is: \[ \text{Volume displaced} = \text{Final Volume} - \text{Initial Volume} \] \[ = 105.00 \, \text{L} - 100.00 \, \text{L} \] \[ = 5.00 \, \text{L} \] Thus, the volume of the aluminum block is 5.00 liters. ### Correct Answer - **5.00 L** This solution illustrates the principle of volume displacement, where the submersion of an object in a fluid increases the fluid's apparent volume by an amount equal to the volume of the object.
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