60 N 95 kPa mp4 kg A- 35 cm A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 4 kg and across-sectional area of 35 cm?. An extended spring above the piston exerts a force of 60 N on the piston. If the atmospheric pressure is 95 КРа, The mass that should be added to double the pressure inside the cylinder for atmospheric pressure of 95 KPa is Select one: O a. 33.8 Kg b. 35.8 Kg O c. 32.8 Kg O d. 31.8 Kg www
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- Question 23 A gas is contained in a vertical, frictionless piston- cylinder device. The piston has a mass of 3.2 kg and a cross-sectional area of 35 cm2. A compressed spring above the piston exerts a force of 150 N on the piston. If the atmospheric pressure is 95 kPa, determine the absolute pressure inside the cylinder in kPa.P4Four closed tanks, A, B, C, and D, each contain an ideal gas. The table gives the absolute pressure and volume of the gas in each tank. In each case, there is 0.19 mol of gas. Using this number and the data in the table, compute the temperature of the gas in each tank. Absolute pressure (Pa) Volume (m³) A 25.0 4.0 B 30.0 5.0 C 20.0 5.0 D 2.0 75
- Below the surface of the sea water where the pressure is P=2.45x10^5 Pa and the temperature i 5C, a diver exhales an air bubble having volume of 1cm^3. If the surface temperature of the sea is 20C. What is the volume of the bubble just before it breaks the surface? Assume air in the bubble to be an ideal gas.A closed, rigid container with a given mass of helium gas is heated until the temperature is doubled. Which of the following statements is TRUE? A The pressure of the gas is unchanged, because there is no relationship between temperature and pressure. The pressure of the gas is unchanged, because helium gas is lighter than the air outside the container. The pressure of the gas also doubles, because temperature and pressure are directly related. D. The pressure of the gas is halved, because temperature and pressure is inversely related. ©2021 Iluminate Education TM, Inc.Calculate the temperature T of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.09 x 10-21 J. T = K What is the total translational kinetic energy Krans of all the molecules of this sample when it contains 1.55 moles of gas? Ktrans = J
- If 1.2 mol of oxygen gas is confined in a 10-L bottle under a pressure of 3.0 atm , what is the average translational kinetic energy of an oxygen molecule? Express your answer using two significant figures. Hν ΑΣφ к- J Submit Request AnswerQuestion A2 An ideal gas occupies a volume of 1.75 cm³ at 30°C and atmospheric pressure. Calculate the number of molecules of gas in the container. (1 atm = 1.013 x 105 Pa)A vertical cylindrical tank contains 1.80 mol of an ideal gas tinder a pressure of 0.300 atm at 20.0°C. The round part of the tank has a radius of 10.0 cm, and the gas is supporting a piston that can move up and down in the cylinder without friction. There is a vacuum above the piston. What is the mass of this piston?
- The ideal gas law is given by, PV=nRT. According to the ideal gas law equation, if you plot 1/P as the y axis and V as the x axis, the slope is: O nRT 1 nR 1 nRT O nRA container with volume 1.64 L is initially evacuated. Then it is filled with 0.226 g of N2. Assume that the pressure of the gas is low enough for the gas to obey the ideal-gas law to a high degree of accuracy. If the root-mean-square speed of the gas molecules is 182 m/s, what is the pressure of the gas?Q.37. What is a gas called that is not an ideal gas? Do such gases exist?