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In a cert top ring is 2.5 mm (0.1 in.). At 90° after HDC on the power stroke, the piston is moving downward at 11 m/s (36 ft/s) and the combustion gas pressure is ness of the 550 kPa (80 psi). o Calculate the area of contact between the top ring and the cylinder liner. h) Assuming the gas pressure on the inside edge of the ring acts on an area essentially equal to that calculated in part a, calculate the normal force due to gas pressure. () Also calculate the normal force due to ring tension, assuming ring tension is equivalent to 50 kPa (7.25 psi) of gas pressure, and the total normal force FN acting on the ring. liner

In a cert top ring is 2.5 mm (0.1 in.). At 90° after HDC on the power stroke, the piston is moving downward at 11 m/s (36 ft/s) and the combustion gas pressure is ness of the 550 kPa (80 psi). o Calculate the area of contact between the top ring and the cylinder liner. h) Assuming the gas pressure on the inside edge of the ring acts on an area essentially equal to that calculated in part a, calculate the normal force due to gas pressure. () Also calculate the normal force due to ring tension, assuming ring tension is equivalent to 50 kPa (7.25 psi) of gas pressure, and the total normal force FN acting on the ring. liner

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top ring is 2.5 mm (0.1 in.). At 90° after HDC on the power stroke, the piston is moving downward at 11 m/s (36 ft/s) and the combustion gas pressure is Solve P13.1 PROBLEm 550 kPa (80 psi). a Calculate the area of contact between the top ring and the cylinder liner. h) Assuming the gas pressure on the inside edge of the ring acts on an area essentially equal to that calculated in part a, calculate the normal force due to gas pressure. O Also calculate the normal force due to ring tension, assuming ring tension is equivalent to 50 kPa (7.25 psi) of gas pressure, and the total normal force Fy acting on the ring. (d) Assuming the coefficient of sliding friction between the ring and liner is 0.42, calculate the shear force F, acting on the ring and the power absorbed by friction on the ring. A Reconsider P13.1, but assume that an oil film of 0.1 mm (0.004 in.) thickness hetween the ring and liner has put the ring in fully hydrodynamic lubrication, Also, assume the dynamic viscosity of the SAE 30 oil is 10 mPars (cP) (a) Calculate the shear force on the ring. (b) Calculate the power absorbed by friction on the ring. (Note that fully hydrodynamic lubrication would not prevail at the ends of the piston stroke.) en (n 00A in thickness
Transcribed Image Text:top ring is 2.5 mm (0.1 in.). At 90° after HDC on the power stroke, the piston is moving downward at 11 m/s (36 ft/s) and the combustion gas pressure is Solve P13.1 PROBLEm 550 kPa (80 psi). a Calculate the area of contact between the top ring and the cylinder liner. h) Assuming the gas pressure on the inside edge of the ring acts on an area essentially equal to that calculated in part a, calculate the normal force due to gas pressure. O Also calculate the normal force due to ring tension, assuming ring tension is equivalent to 50 kPa (7.25 psi) of gas pressure, and the total normal force Fy acting on the ring. (d) Assuming the coefficient of sliding friction between the ring and liner is 0.42, calculate the shear force F, acting on the ring and the power absorbed by friction on the ring. A Reconsider P13.1, but assume that an oil film of 0.1 mm (0.004 in.) thickness hetween the ring and liner has put the ring in fully hydrodynamic lubrication, Also, assume the dynamic viscosity of the SAE 30 oil is 10 mPars (cP) (a) Calculate the shear force on the ring. (b) Calculate the power absorbed by friction on the ring. (Note that fully hydrodynamic lubrication would not prevail at the ends of the piston stroke.) en (n 00A in thickness
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