The physics unit of Weber that we used this semester is equivalent to: O T OTm m2 O Tm2
Q: e z + e Calculate: (AxB). (AXB) A- c the magnitude and dire ction of A.C
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Q: [kgm/s] / [kgm3 /s2 ] =
A: Required [kgm/s] / [kgm3 /s2 ] =
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Q: ok i understand much better now but where did the 0.258 come from (multiplied to 17)
A: Moment of force
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A: In answer A we get Q1+Q2 =27 μCand we know micro coulomb( μC) =10-6 C So answer A has 10-6
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A: Given AB = 44 cmBC = 20 cmAO = 4 cm
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Q: Net torque ( T): ET, = 0 Tcw = Teew %3D Teew= WgrcG Tew = wir1 ccw % Difference between Tew and Tcew
A: Given data is as per question: m1=8.2×10-2 kgr1=0.247 mrCG=0.254 m
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The physics unit of Weber that we used this semester is equivalent to:
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- Please!!! check both papers it is a b and cIn an experiment, 2 velocities are calculated: 0.550 m/s and 0.590 m/s. What is the % Difference?surface, denoted by “g”. In this imaginary experiment, you have measured g three times. The values you obtain are: g1 = 10.2 meters per second squared (m/s2) g2 = 10.4 m/s2 g3 = 10.0 m/s2 To find the Average Value of g, denoted by gav, simple add up the experimental values and divide by the number of experimental values you have: g1 + g2 + g3 10.2 + 10.4 + 10 gav = __________ = ____________ = 10.2 m/s2 . 3 3 Percent Error (PE) To find the Percent Error (PE), you compare the average experimental value to the standard or handbook value of the physical quantity you are measuring. The Standard Value of gravitational acceleration at Earth’s surface , gst, is 9.8 m/s2. Mathematically, PE is defined as: (Average - Standard)…
- The dimensional equivalence of the quantity "momentum" in terms of the fundamental quantities (mass, length, time) is: O MLT¹ Ob-ML²T-2 OC. MLT. Od MLT 2Please walk me through the solution using variables, not the given values.Please help with my physics problem (see image, there are two parts to this problem)