The physical characteristics of a cell influence how it functions. For example, the surface area and volume of a cell affect how efficiently waste is removed from the cell via diffusion. The table below shows data for four different cuboidal cells. Cuboidal cell Side length (um) Cell A 1 Cell B Cell C Cell D 4 Surface area of a cube: A = 6s2 Volume of a cube: V = s Using the information from the table, what is the surface-area-to-volume ratio for the cuboidal cell that removes waste via diffusion most efficiently? 2 3

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**Cell Size and Efficiency of Waste Removal**

The physical characteristics of a cell influence how it functions. For example, the surface area and volume of a cell affect how efficiently waste is removed from the cell via diffusion.

The table below shows data for four different cuboidal cells.

| Cuboidal cell | Side length (µm) |
| ------------- | ----------------- |
| Cell A        | 1                 |
| Cell B        | 2                 |
| Cell C        | 3                 |
| Cell D        | 4                 |

**Formulas:**
- **Surface area of a cube:** \(A = 6s^2\)
- **Volume of a cube:** \(V = s^3\)

Using the information from the table, what is the surface-area-to-volume ratio for the cuboidal cell that removes waste via diffusion most efficiently?

\[ \text{µm}^{-1} \]

[Show Calculator]

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The explanation for the formulas is important for students to calculate the surface-area-to-volume ratio. Cuboidal cell examples and their side lengths provide data for practical application of the formulas.

To find the surface-area-to-volume ratio, students will use the side lengths provided, apply the formulas to compute surface area and volume for each cell, and then determine the ratio for each cell to identify which one removes waste the most efficiently.
Transcribed Image Text:--- **Cell Size and Efficiency of Waste Removal** The physical characteristics of a cell influence how it functions. For example, the surface area and volume of a cell affect how efficiently waste is removed from the cell via diffusion. The table below shows data for four different cuboidal cells. | Cuboidal cell | Side length (µm) | | ------------- | ----------------- | | Cell A | 1 | | Cell B | 2 | | Cell C | 3 | | Cell D | 4 | **Formulas:** - **Surface area of a cube:** \(A = 6s^2\) - **Volume of a cube:** \(V = s^3\) Using the information from the table, what is the surface-area-to-volume ratio for the cuboidal cell that removes waste via diffusion most efficiently? \[ \text{µm}^{-1} \] [Show Calculator] --- The explanation for the formulas is important for students to calculate the surface-area-to-volume ratio. Cuboidal cell examples and their side lengths provide data for practical application of the formulas. To find the surface-area-to-volume ratio, students will use the side lengths provided, apply the formulas to compute surface area and volume for each cell, and then determine the ratio for each cell to identify which one removes waste the most efficiently.
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