In each of the following substances NaH, H2 and H2S , hydrogen is assigned an oxidation number of +1. Is this correct? Explain your reasoning. Answer in complete sentences.
In each of the following substances NaH, H2 and H2S , hydrogen is assigned an oxidation number of +1. Is this correct? Explain your reasoning. Answer in complete sentences.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In each of the following substances NaH, H2 and H2S , hydrogen is assigned an oxidation number of +1. Is this correct? Explain your reasoning.
Answer in complete sentences.
![### Determining Oxidation Numbers of Hydrogen
#### Question
In each of the following substances \( \text{NaH} \), \( \text{H}_2 \), and \( \text{H}_2\text{S} \), hydrogen is assigned an oxidation number of +1. Is this correct? Explain your reasoning.
Answer in complete sentences.
#### Answer Box
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In determining the oxidation number of hydrogen in various compounds, it is important to follow a few key rules about how oxidation numbers are assigned:
1. **Rules for Oxidation Numbers:**
- For an atom in its elemental form (e.g., \( \text{H}_2 \)), the oxidation number is always 0.
- For monatomic ions, the oxidation number is equal to the charge of the ion.
- Hydrogen generally has an oxidation number of +1 when bonded to non-metals and -1 when bonded to metals.
2. **Oxidation Number in \( \text{NaH} \):**
- Sodium (Na) is a metal and typically forms a +1 oxidation state.
- Therefore, in \( \text{NaH} \), hydrogen would carry a -1 oxidation state to balance the +1 charge of sodium.
- Hence, assigning hydrogen an oxidation number of +1 in \( \text{NaH} \) is incorrect.
3. **Oxidation Number in \( \text{H}_2 \):**
- \( \text{H}_2 \) is hydrogen in its elemental form.
- Hence, the oxidation number of hydrogen in \( \text{H}_2 \) is 0.
- Assigning an oxidation number of +1 to hydrogen in \( \text{H}_2 \) is incorrect.
4. **Oxidation Number in \( \text{H}_2\text{S} \):**
- In \( \text{H}_2\text{S} \), sulfur is a non-metal.
- Hydrogen is bonded to a non-metal and typically has an oxidation number of +1 in such compounds.
- Therefore, assigning an oxidation number of +1 to hydrogen in \( \text{H}_2\text{S} \) is correct.
In conclusion, hydrogen is correctly assigned an oxidation number of +1 in \( \text{H}_2\text{S} \). However](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54f1e0b6-1968-49a8-ad8c-1134cba15596%2F1a50f4f3-dde8-4aa5-9c15-c26485c2af6c%2Fxsp6va3_processed.png&w=3840&q=75)
Transcribed Image Text:### Determining Oxidation Numbers of Hydrogen
#### Question
In each of the following substances \( \text{NaH} \), \( \text{H}_2 \), and \( \text{H}_2\text{S} \), hydrogen is assigned an oxidation number of +1. Is this correct? Explain your reasoning.
Answer in complete sentences.
#### Answer Box
[Text Editor Interface]
In determining the oxidation number of hydrogen in various compounds, it is important to follow a few key rules about how oxidation numbers are assigned:
1. **Rules for Oxidation Numbers:**
- For an atom in its elemental form (e.g., \( \text{H}_2 \)), the oxidation number is always 0.
- For monatomic ions, the oxidation number is equal to the charge of the ion.
- Hydrogen generally has an oxidation number of +1 when bonded to non-metals and -1 when bonded to metals.
2. **Oxidation Number in \( \text{NaH} \):**
- Sodium (Na) is a metal and typically forms a +1 oxidation state.
- Therefore, in \( \text{NaH} \), hydrogen would carry a -1 oxidation state to balance the +1 charge of sodium.
- Hence, assigning hydrogen an oxidation number of +1 in \( \text{NaH} \) is incorrect.
3. **Oxidation Number in \( \text{H}_2 \):**
- \( \text{H}_2 \) is hydrogen in its elemental form.
- Hence, the oxidation number of hydrogen in \( \text{H}_2 \) is 0.
- Assigning an oxidation number of +1 to hydrogen in \( \text{H}_2 \) is incorrect.
4. **Oxidation Number in \( \text{H}_2\text{S} \):**
- In \( \text{H}_2\text{S} \), sulfur is a non-metal.
- Hydrogen is bonded to a non-metal and typically has an oxidation number of +1 in such compounds.
- Therefore, assigning an oxidation number of +1 to hydrogen in \( \text{H}_2\text{S} \) is correct.
In conclusion, hydrogen is correctly assigned an oxidation number of +1 in \( \text{H}_2\text{S} \). However
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