The Pew Social Media Update 2014 surveyed 1,597 adult internet users on which social media websites they use. Of the users surveyed, 1,134 responded "yes" when asked if they use Facebook. Identify the values needed to calculate a confidence interval at the 95% confidence level. Then find the confidence interval

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: As part of the Pew Internet and American Life Project,, researchers conducted two surveys in late…

A: Given: n1= 800 ,x1= 584 n2= 2253 ,x2= 1059 At 95.0 % confidence level , z score= 1.96 Need to find…

Q: A local news outlet reported that 56% of 600 randomly sampled Kansas residents planned to set off…

A: We have given that,  Sample proportion (p̂) = 56% = 0.56 and sample size (n) = 600 Then,  We will…

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: When constructing a confidence interval, if we construct a confidence interval with a 95% confidence…

A: The general formula for the width of the confidence interval is,

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Solution

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1227 males​…

A:

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: You're considering going to graduate school, and you would like to know how many people would…

A: From the provided information Sample size (n) = 29, People who recommend x = 9 The sample proportion…

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: It is known that ticks in York County carry the Lyme disease.  In a representative sample of 200…

A: Let n=sample size, X=number of Carry disease. p^=x/n  X=167, n=200

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: 99% confidence interval for the proportion of the high school students who have been cyberbullied,…

A: Given that Sample size n = 14795 Number of high school students who have cyberbullied, X = 2219 The…

Q: a survey of 1083 people, 585 answered "yes" to a particular question. Construct a 90% confidence…

A:

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: A Pew Internet poll asked 4272 U.S. adults about their use of smart watches and fitness trackers. A…

A: Given,n=4272X=897

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: ed 1294 people whether they performed any volunteer work during the past year. A total of 517 people…

A: The sample proportion is computed as follows,

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: A new survey found that out of a random sample of 300 high school students throughout the country…

A: From the provided information, Sample size (n) = 300 83% of them still planned on taking the…

Q: A sample of 1,000 employees in an international company was taken to estimate the average…

A: Confidence interval of mean is given by, (X bar + - Z* sigma/√n) Where X bar is mean and sigma is…

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: In a survey of 3102 adults,1401 say they have started paying bills online in the last year.…

A: Obtain the 99% confidence interval for the true population proportion. The 99% confidence interval…

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare…

A: Answer Favorable cases [x] = 1230The sample size [n] = 2105

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: Insurance companies are interested in knowing the popul drivers who always buckle up before riding…

A: Given data,No of people surveyed n=387who claims to buckle up is x=311Construct a 93 % CI?

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

A:

Q: Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90%…

A: We have given that n=848, X=144, C.I=90%=0.90

Q: In a survey of 2291 ​adults, 708 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.