Items in parentheses are the solutions to the problem The particle of mass m = 0.6 kg is attached to the end of the light rigid bar of length l = 0.7 m.The system is released from rest while in the horizontal position shown, at which the torsional springof stiffness kt = 15 N.m/rad is undeflected. A variable moment M = 120, where M is the momentin N.m and is the angle of the bar with the horizontal in radians, is acting on the bar, as shown.Determine (a) the angular velocity of the bar as it passes the orientation 0 = 40°, and (b) the anglewhere the bar stops momentarily. (w = 3.61 rad/s, 0 = 94.8°)MᎾlm

Answered: The particle of mass m = 0.6 kg is…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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4. A uniform disc of mass m = 3 kg and radius R= 0.5 may roll without slip on the 30 degree incline shown. An elastic spring of stiffness k= 100 newtons/meter is connected to the center C of the disc. Initially, the disc is held in place in the position shown, with the spring neither stretched nor compressed and with the disc at rest. At t = 0 the disc is released and is subjected to a constant force of Fo = 30 newtons along the incline. Determine the maximum speed achieved by the disc center C as the disc moves up the incline. For gravity use g = 10 m/sec². (note: initially the constant force Fo will be greater than the forces exerted by the spring and by gravity, and the disc will accelerate up the incline; but there will come a distance x along the incline after which the spring force + gravity will overtake the force Fo, and the disc will then decelerate). gravity Fo= 30 N 30° no friction
Figure shows a system of cylinder (m = 55 kg) and a load (m = 62 kg) connected through a rope. The system is released from rest and the load L moves along the inclined surface. The kinetic coefficient of friction between the load and the inclined surface is 0.22. The radius of gyration of the cylinder is 0.8 m. Take d1 = 0.5 m, d2 = 1.4 m, and a = 66°. Determine the angular velocity of the cylinder after the load L slides 1.6 m on the inclined surface. d2 d1 C The angular velocity of the cylinder is, [rad/s].
Figure shows a system of cylinder (m = 50 kg) and a load (m = 30 kg) connected through a rope. The system is released from rest and the load L moves along the inclined surface. The kinetic coefficient of friction between the load and the inclined surface is 0.22. The radius of gyration of the cylinder is 0.8 m. Take d1 = 0.5 m, d2 = 1.4 m, and a = 34°. Determine the angular velocity of the cylinder after the load L slides 1.6 m on the inclined surface. d2 d1 C
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (3) The stretched spring length of the spring at the state 1 is_ places) 2₂ State 2 7717 State 1 _(m) (two decimal
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (11) The angular velocity at the state 2?_ _(rad/s) (two decimal places) 111441 L₂ State 2 State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 0-0°. The spring's length at the state 2 is L2=4 m. (12) The kinetic energy at the state 2? (N-m) (two decimal places) LLLLKAL 2₂ तो State 2 Li State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 0-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (kg-m²) (two (8) The mass moment of inertial about the mass center G is IG= decimal places) HILAI L₂ State 2 State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (10) The kinetic energy at the state1?__ (N-m) (two decimal places) LLLLLLL L₂ State 2 C State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is (two decimal places) HILAI ܪܐ 717 State 2 State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (5) The stretched spring length of the spring at the state 2 is_ places) HULK ܪܐ TG नेता State 2 State 1 _(m) (two decimal
A 20kg slender rod AB is pinned to a roller at A that slides freely along the slot as shown in the figure below. The rod is released from the rest at an angle of 30. At the same time, a couple moment of M = 5 N.m in clockwise direction is applied at its centre of gravity. If immediately after the release the acceleration of the roller at A is 43m/s, determine the reaction forces at the pin connection at Point A.
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k-2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (6) The elastic potential energy the state 2 is HILAI L₂ # State 2 ZG State 1 (N-m) (two decimal places)

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