Homework Help is Here – Start Your Trial Now!
Math
Statistics
The oxygen equivalence number of a weld is a number that can be used to predict properties such as hardness, strength, and ductility. The article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds" (D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s–136s) presents several equations for computing the oxygen equivalence number of a weld. An equation designed to predict the strength of a weld is X = 1.12C + 2.69N + O – 0.21 Fe, where X is the oxygen equivalence, and C, N, O, and Fe are the amounts of carbon, nitrogen, oxygen, and iron, respectively, in 0.0247, HN weight percent, in the weld. Suppose that for welds of a certain type, Hc = 0.0255, Ho = 0.0340, and OFe = 0.0597, ởC 0.0131, ƠN = 0.0194, oo 0.1668, µFe 0.0413. Furthermore assume that correlations are given by PC.N = -0.44, PC.0 = 0.58, PC,Fe = 0.39, PN,0 = -0.35. = -0.32, PN.Fe = 0.09, and PO,Fe Find µx- a. Find Cov(C, H), Cov(C, O), Cov(C, Fe), Cov(N, 0), Cov(N, Fe), and Cov(O, Fe). Find Ox. b. C.

The oxygen equivalence number of a weld is a number that can be used to predict properties such as hardness, strength, and ductility. The article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds" (D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s–136s) presents several equations for computing the oxygen equivalence number of a weld. An equation designed to predict the strength of a weld is X = 1.12C + 2.69N + O – 0.21 Fe, where X is the oxygen equivalence, and C, N, O, and Fe are the amounts of carbon, nitrogen, oxygen, and iron, respectively, in 0.0247, HN weight percent, in the weld. Suppose that for welds of a certain type, Hc = 0.0255, Ho = 0.0340, and OFe = 0.0597, ởC 0.0131, ƠN = 0.0194, oo 0.1668, µFe 0.0413. Furthermore assume that correlations are given by PC.N = -0.44, PC.0 = 0.58, PC,Fe = 0.39, PN,0 = -0.35. = -0.32, PN.Fe = 0.09, and PO,Fe Find µx- a. Find Cov(C, H), Cov(C, O), Cov(C, Fe), Cov(N, 0), Cov(N, Fe), and Cov(O, Fe). Find Ox. b. C.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
See similar textbooks
icon
Related questions
Question
The oxygen equivalence number of a weld is a number that can be used to predict properties such as hardness, strength, and ductility. The article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds" (D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s–136s) presents several equations for computing the oxygen equivalence number of a weld. An equation designed to predict the strength of a weld is X = 1.12C + 2.69N + O – 0.21 Fe, where X is the oxygen equivalence, and C, N, O, and Fe are the amounts of carbon, nitrogen, oxygen, and iron, respectively, in 0.0247, HN weight percent, in the weld. Suppose that for welds of a certain type, Hc = 0.0255, Ho = 0.0340, and OFe = 0.0597, ởC 0.0131, ƠN = 0.0194, oo 0.1668, µFe 0.0413. Furthermore assume that correlations are given by PC.N = -0.44, PC.0 = 0.58, PC,Fe = 0.39, PN,0 = -0.35. = -0.32, PN.Fe = 0.09, and PO,Fe Find µx- a. Find Cov(C, H), Cov(C, O), Cov(C, Fe), Cov(N, 0), Cov(N, Fe), and Cov(O, Fe). Find Ox. b. C.
Transcribed Image Text:The oxygen equivalence number of a weld is a number that can be used to predict properties such as hardness, strength, and ductility. The article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds" (D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s–136s) presents several equations for computing the oxygen equivalence number of a weld. An equation designed to predict the strength of a weld is X = 1.12C + 2.69N + O – 0.21 Fe, where X is the oxygen equivalence, and C, N, O, and Fe are the amounts of carbon, nitrogen, oxygen, and iron, respectively, in 0.0247, HN weight percent, in the weld. Suppose that for welds of a certain type, Hc = 0.0255, Ho = 0.0340, and OFe = 0.0597, ởC 0.0131, ƠN = 0.0194, oo 0.1668, µFe 0.0413. Furthermore assume that correlations are given by PC.N = -0.44, PC.0 = 0.58, PC,Fe = 0.39, PN,0 = -0.35. = -0.32, PN.Fe = 0.09, and PO,Fe Find µx- a. Find Cov(C, H), Cov(C, O), Cov(C, Fe), Cov(N, 0), Cov(N, Fe), and Cov(O, Fe). Find Ox. b. C.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman
SEE MORE TEXTBOOKS