The output below estimates the following regression Treati = • Bo B1 Female; + ɛi Based on the results, which statement is most accurate. reg treat st_femalel Source SS df MS Number of obs = 619 F(1, 617) = 0.01 Model Residual .003006351 154.71428 1 .003006351 617 .250752479 Prob > F R-squared = 0.9128 = 0.0000 Total 154.717286 618 250351595 Adj R-squared Root MSE = -0.0016 = .50075 treat Coefficient Std. err. t P>|t| [95% conf. interval] st_female1 _cons .0051549 .5033557 .0470789 0410232 0.11 0.913 12.27 0.000 0872993 0976092 4227937 .5839177 In the treatment group, the fraction female is much higher than in the control group In the treatment group, the fraction female is slightly higher than in the control group In the treatment group, the fraction female is slightly lower than in the control group In the treatment group, the fraction female is much lower than in the control group
The output below estimates the following regression Treati = • Bo B1 Female; + ɛi Based on the results, which statement is most accurate. reg treat st_femalel Source SS df MS Number of obs = 619 F(1, 617) = 0.01 Model Residual .003006351 154.71428 1 .003006351 617 .250752479 Prob > F R-squared = 0.9128 = 0.0000 Total 154.717286 618 250351595 Adj R-squared Root MSE = -0.0016 = .50075 treat Coefficient Std. err. t P>|t| [95% conf. interval] st_female1 _cons .0051549 .5033557 .0470789 0410232 0.11 0.913 12.27 0.000 0872993 0976092 4227937 .5839177 In the treatment group, the fraction female is much higher than in the control group In the treatment group, the fraction female is slightly higher than in the control group In the treatment group, the fraction female is slightly lower than in the control group In the treatment group, the fraction female is much lower than in the control group
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter12: Points, Classes, Virtual Functions And Abstract Classes
Section: Chapter Questions
Problem 17SA
Related questions
Question
![The output below estimates the following regression
Treati
=
•
Bo B1 Female; + ɛi
Based on the results, which statement is most accurate.
reg treat st_femalel
Source
SS
df
MS
Number of obs =
619
F(1, 617)
=
0.01
Model
Residual
.003006351
154.71428
1 .003006351
617 .250752479
Prob > F
R-squared
=
0.9128
=
0.0000
Total
154.717286
618 250351595
Adj R-squared
Root MSE
=
-0.0016
=
.50075
treat
Coefficient Std. err.
t
P>|t|
[95% conf. interval]
st_female1
_cons
.0051549
.5033557
.0470789
0410232
0.11 0.913
12.27 0.000
0872993
0976092
4227937
.5839177
In the treatment group, the fraction female is much higher than in the control group
In the treatment group, the fraction female is slightly higher than in the control group
In the treatment group, the fraction female is slightly lower than in the control group
In the treatment group, the fraction female is much lower than in the control group](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2225a944-df22-4b7d-83fa-578c45dad04f%2F8e749b47-11a7-4bee-b219-3dd2d036227e%2F49291l4_processed.png&w=3840&q=75)
Transcribed Image Text:The output below estimates the following regression
Treati
=
•
Bo B1 Female; + ɛi
Based on the results, which statement is most accurate.
reg treat st_femalel
Source
SS
df
MS
Number of obs =
619
F(1, 617)
=
0.01
Model
Residual
.003006351
154.71428
1 .003006351
617 .250752479
Prob > F
R-squared
=
0.9128
=
0.0000
Total
154.717286
618 250351595
Adj R-squared
Root MSE
=
-0.0016
=
.50075
treat
Coefficient Std. err.
t
P>|t|
[95% conf. interval]
st_female1
_cons
.0051549
.5033557
.0470789
0410232
0.11 0.913
12.27 0.000
0872993
0976092
4227937
.5839177
In the treatment group, the fraction female is much higher than in the control group
In the treatment group, the fraction female is slightly higher than in the control group
In the treatment group, the fraction female is slightly lower than in the control group
In the treatment group, the fraction female is much lower than in the control group
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