The orbit of a 1.5 x 1010 kg comet around the Sun is elliptical, with an aphelion distance of 33.0 AU and perihelion distance of 0.855 AU. (Note: 1 AU = one astronomical unit = the average distance from the Sun to the Earth = 1.496 × 1011 m.) (a) What is its orbital eccentricity? (b) What is its period? (Enter your answer in yr.) yr (c) At aphelion what is the potential energy (in J) of the comet-Sun system?
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- A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]Suppose that the moon rotates on its axis once every 29.5 days. The equator lies on a circle with a radius of 1079 miles. (a) Find the angular speed of a point on its equator in radians per year (365 days). (b) Find the linear speed of a point on the equator in miles per years. Do not round any intermediate computations, and round your answer to the nearest whole number.The moon Phobos orbits around Mars with a semi-major axis of 9376 km, and an orbital period of 7.65 hours. If NASA wanted to put a satellite in a circular orbit around Mars with an orbital period of 50.0 hours, what should the radius of the orbit be, in km?
- Calculate the period of a satellite orbiting a planet with the mass 8.7 x 1022 kg given the height of the satellite's orbit is 300 km and the radius of the planet is 2000 km. Provide your answer in Sl units.Given the orbital radius and period of a moon, derive an algebraic solution for the mass of the planet that moon orbits. Watch those units, convert to SI.A satellite is in a circular orbit at an altitude of 1.5 earth radii, with an inclination of 90°. Calculate the satellite's orbital period in minutes. Report your answer to three significant digits (e.g. 123). For the radius of the earth use RE = 6371 km; for the gravitation acceleration use g = 9.81 m/s2. What is the orbital period in minutes?
- According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.92 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s. Answer: Choose...A geosynchronous orbit is one in which the satellite stays in the same relative position above the earth, as the earth rotates. To do so, the satellite needs to have an orbital period of 1 day. Given that the moon has an orbital period of 27.3 days and a semi-major axis of 384,000 km, determine the radius of a geosynchronous orbit using Kepler's 3rd law. Enter your answer in km.The orbit of a 1.5 x 1010 kg comet around the Sun is elliptical, with an aphelion distance of 11.0 AU and perihelion distance of 0.890 AU. (Note: 1 AU = one astronomical unit = the average distance from the Sun to the Earth = 1.496 x 101" m.) (a) What is its orbital eccentricity? (b) What is its period? (Enter your answer in yr.) yr (c) At aphelion what is the potential energy (in J) of the comet-Sun system?
- Kepler’s Law relates the period T ( in a sec) of a satellite to the distance from the center of the earth r (in m) to some physical constants as shown: T2 = (2π/ G ME) r3 Where G = Universal Constant of Gravitation and ME is the mass of the earth. A stationary satellite is one that circles the earth in a circular orbit but stays exactly above the same spot on the earth. Calculate the distance above the earth in m for this “geo-synchronous satellite” to orbit, then convert that height to miles.Could I please have some guidance on the steps for this? An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.450×105 km and the planet has a radius of 3.850×103 km and a mass of 4.90×1022 kg , how long (in days) does it take the moon to make one revolution around the planet? The gravitational constant is 6.67×10−11N·m2/kg2.An astronomer observes that a small moon is in circular orbit around a distant planet. If the moon has a period of 150.0 hours and an orbital radius of 3.70 x 10^7 m, what is the mass of the planet? Submit your answer in units of 10^23 kg.