An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 1.870 times Earth's. What is the asteroid's orbital period, in terms of Earth years?
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An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 1.870 times Earth's. What is the asteroid's orbital period, in terms of Earth years?
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- According to Lunar Laser Ranging experiments the average distance L M from the Earth to the Moon is approximately 3.85 × 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). Calculate mass of the EarthIf a planet has a period of 8 years, what is its average distance from the Sun, in astronomical units? Assume thatthe mass of the planet is small compared to the Sun and thatthe average distance from the Sun is the same as the semimajoraxis. Make sure you express your answer with at least one digitafter the decimal point.A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what is the mass of the planet?
- An asteroid is orbiting the sun in a stable orbit with a period (its “year”) of 860.623 days (Earth-days). What is the ratio of the asteroids distance from the sun to the Earth's distance from the sun? Answer is 1.8. Please show steps.A planet with mass 9.69x1023 kg orbits a star with mass 9.21x1030 kg. The orbit is circular, and the distance from the planet to the sun is 225x106 km. What is the length of a year on this planet? Give your answer in earth years (1 earth year = 31,557,600 seconds).The mean radius of earth from the Sun is 0.67 times the mars mean distancxe of mars from the sun. What is the time (in years) for mars to orbit the sun?
- The mean distance of an asteroid from the Sun is 1.74 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for the asteroid to make one revolution around the Sun.An Earth satellite has an orbital period of 5.3 h. What is its orbital radius? (ME = 5.98 x 1024 kg)Help me to solve this problem step by step and give answer as a 3 significant figures
- The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 9.16 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.91 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s. Answer: Choose...