) The object lies at position 15.1 cm. (Enter the value for q in cm.). 9 = -21.1 cm M = -1.39 How is an image oriented when formed by a converging lens, provided the object is closer to the lens than the focal point of the lens? Does this orientation correspond to a positive or negative magnification? Select all that apply to part (b). Oreal ✔virtual O upright ✔inverted no image X Carefully review the sign convention for image position. (Is the image position positive or negative? Which sign indicates a real or virtual image?) Review the sign convention for magnification (Which cign indicator an upright or inverted image2)
Ray Optics
Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is an optics model that explains light propagation using rays. In an optical device, a ray is a direction along which light energy is transmitted from one point to another. Geometric optics assumes that waves (rays) move in straight lines before they reach a surface. When a ray collides with a surface, it can bounce back (reflect) or bend (refract), but it continues in a straight line. The laws of reflection and refraction are the fundamental laws of geometrical optics. Light is an electromagnetic wave with a wavelength that falls within the visible spectrum.
Converging Lens
Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on the other side of the lens.
Plano-Convex Lens
To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.
Lateral Magnification
In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This process is mainly done to get an even more detailed view of the object by scaling up the image. A lot of daily life examples for this can be the use of magnifying glasses, projectors, and microscopes in laboratories. This plays a vital role in the fields of research and development and to some extent even our daily lives; our daily activity of magnifying images and texts on our mobile screen for a better look is nothing other than magnification.
not sure what im doing wrong on parts B and C
![(c) The object lies at position 345 cm. (Enter the value for q in cm.)
9 = 62.9
✔
cm
M = 0.18
X
How is an image oriented when formed by a converging lens, provided the object is farther from the lens than the focal point of the lens? Does this orientation
correspond to a positive or negative magnification?
Select all that apply to part (c).
✔real
virtual
✔upright
inverted
no image
Carefully review the sign convention for image position. (Is the image position positive or negative? Which sign indicates a real or virtual image?) Review the sign
convention for magnification. (Which sign indicates an upright or inverted image?)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84f39a0e-1c16-43ec-bcb3-7f889ca233a2%2F2930f719-dac0-47b2-83f8-802c89e54dd0%2Febenm7_processed.png&w=3840&q=75)
![In the following three scenarios, an object is located on one side of a converging lens. In each case, you must determine if the lens forms an image of this object. If it does
you also must determine the following.
• whether the image is real or virtual
• whether the image is upright or inverted
the image's location, q
• the image's magnification, M
The focal length is f = 53.0 cm for this lens.
Set both q and M to zero if no image exists.
Note: If q appears to be infinite, the image does not exist (but nevertheless set q to 0 when entering your answers to that particular scenario).
(a) The object lies at position 53.0 cm. (Enter the value for q in cm.)
q = 0
cm
M = 0
Select all that apply to part (a).
U real
0000
virtual
O upright
inverted
✔no image
✓
(b) The object lies at position 15.1 cm. (Enter the value for q in cm.)
9 = -21.1
cm
M =
-1.39
X
How is an image oriented when formed by a converging lens, provided the object is closer to the lens than the focal point of the lens? Does this orientation
correspond to a positive or negative magnification?
Select all that apply to part (b).
U real
✔virtual
O upright
✓inverted
no image
X
Carefully review the sign convention for image position. (Is the image position positive or negative? Which sign indicates a real or virtual image?) Review the sign
convention for magnification. (Which sign indicates an upright or inverted image?)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84f39a0e-1c16-43ec-bcb3-7f889ca233a2%2F2930f719-dac0-47b2-83f8-802c89e54dd0%2Fech69wn_processed.png&w=3840&q=75)
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