Q=+24µC 6.m 8 m
Related questions
Question
Where is 1/10 come from?
And can u explain part b and c
![2. A moving charge, q=+3μC, takes a curved path (see broken curve with arrow)
from point A through point B as it is deflected by its interaction with the charge Q=+24μC. Note
that the +24µC charge remains fixed in the position shown. Neglect gravitational forces and
gravitational energies in this problem.
a. What is the change in the electric potential energy of the system as the + 3μC charged particle
moves from point A to point B?
b. What is the change in the kinetic energy of this +3μC charged particle as it moves from
point A to point B?
c.
Will the speed of the charged particle at point B be greater than or less than the
speed at point A?
6 m
Q = +24µC
8 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68b7ef8c-3890-4ce3-a2c5-3c13928719bf%2F16c5a52c-121d-4c64-b76c-dc5c0b4c3591%2Fxuvsz3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. A moving charge, q=+3μC, takes a curved path (see broken curve with arrow)
from point A through point B as it is deflected by its interaction with the charge Q=+24μC. Note
that the +24µC charge remains fixed in the position shown. Neglect gravitational forces and
gravitational energies in this problem.
a. What is the change in the electric potential energy of the system as the + 3μC charged particle
moves from point A to point B?
b. What is the change in the kinetic energy of this +3μC charged particle as it moves from
point A to point B?
c.
Will the speed of the charged particle at point B be greater than or less than the
speed at point A?
6 m
Q = +24µC
8 m
![@so change
in
electric potential energy
UAB = KQY (AB)
кад
(ㅁ-)
-6
=) DUA-> B = 9×10 9 x 24x10-6 x 3×10 6 (+-10)
(ㅎ-ㅎ)
-3
AUAB = 43.2x10 3 Joule](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68b7ef8c-3890-4ce3-a2c5-3c13928719bf%2F16c5a52c-121d-4c64-b76c-dc5c0b4c3591%2Fnyxm063_processed.jpeg&w=3840&q=75)
Transcribed Image Text:@so change
in
electric potential energy
UAB = KQY (AB)
кад
(ㅁ-)
-6
=) DUA-> B = 9×10 9 x 24x10-6 x 3×10 6 (+-10)
(ㅎ-ㅎ)
-3
AUAB = 43.2x10 3 Joule
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)