e) What is the magnetic torque on the current loop? [0.0187 ) What is the direction of the torque on the current loop? O To the left on the page Towards the bottom of the page Towards the top of the page To the right on the page Can't be determined from the information provided Out of the page O Into the page X Nm

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I need help with part e and f please I got them wrong.
O Towards the bottom of the page
O Towards the top of the page
|
c) If you reverse the direction of the current I2, so that it is going down instead of up, what is magnitude of the NET magnetic
field at point P? (enter a positive number) 3.63e-4
Tesla
Now consider a planar square current loop that is positioned inside of a solenoid, as shown in the figure below.
O
IV
top view: look down into
solenoid from the top.
The square loop has sides of length 0.5 m, and carries current Iloop = 8 Amps. When viewed from the side (left part of the figure),
the plane of the current loop makes an angle of 0 = 32.00 degrees with the axis of the solenoid. The current is going into the
page on the top right segment of the square loop (designated by an "x" with a circle around it), and the current is coming out of
the page on the bottom left segment of the square loop (designated by a dot with a circle around it). When viewed from above
(right panel of figure), the current loop does not look square because the loop is tilted at angle as shown in the left panel.
The solenoid carries a current Isol = 35 Amps, is 3 meters long, and has 250 turns per meter. The direction of the current in the
solenoid produces a magnetic field that points up on the page.
d) What is the magnetic field within the solenoid, due to the current in the solenoid (i.e. you should ignore the magnetic field from
the square current loop in answering this question)? 0.011
Tesla
f) What is the direction of the torque on the current loop?
To the left on the page
O Towards the bottom of the page
O Towards the top of the page
O To the right on the page
O Can't be determined from the information provided
O Out of the page
O Into the page
e) What is the magnetic torque on the current loop? 0.0187
X Nm
Transcribed Image Text:O Towards the bottom of the page O Towards the top of the page | c) If you reverse the direction of the current I2, so that it is going down instead of up, what is magnitude of the NET magnetic field at point P? (enter a positive number) 3.63e-4 Tesla Now consider a planar square current loop that is positioned inside of a solenoid, as shown in the figure below. O IV top view: look down into solenoid from the top. The square loop has sides of length 0.5 m, and carries current Iloop = 8 Amps. When viewed from the side (left part of the figure), the plane of the current loop makes an angle of 0 = 32.00 degrees with the axis of the solenoid. The current is going into the page on the top right segment of the square loop (designated by an "x" with a circle around it), and the current is coming out of the page on the bottom left segment of the square loop (designated by a dot with a circle around it). When viewed from above (right panel of figure), the current loop does not look square because the loop is tilted at angle as shown in the left panel. The solenoid carries a current Isol = 35 Amps, is 3 meters long, and has 250 turns per meter. The direction of the current in the solenoid produces a magnetic field that points up on the page. d) What is the magnetic field within the solenoid, due to the current in the solenoid (i.e. you should ignore the magnetic field from the square current loop in answering this question)? 0.011 Tesla f) What is the direction of the torque on the current loop? To the left on the page O Towards the bottom of the page O Towards the top of the page O To the right on the page O Can't be determined from the information provided O Out of the page O Into the page e) What is the magnetic torque on the current loop? 0.0187 X Nm
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