The null and alternative hypothesis would be: Ho:µ = 3.4 Ho: µ = 3.4 Ho:p = 0.85 Ho:p= 0.85 Ho:p= 0.85 Ho:µ = 3.4 H1:µ + 3.4 H1:µ > 3.4 H1:p < 0.85 H1:p + 0.85 H1:p > 0.85 H1:µ < 3.4 %3D %3D The test is: right-tailed left-tailed two-tailed Based on a sample of 45 people, the sample mean GPA was 3.41 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
The null and alternative hypothesis would be: Ho:µ = 3.4 Ho: µ = 3.4 Ho:p = 0.85 Ho:p= 0.85 Ho:p= 0.85 Ho:µ = 3.4 H1:µ + 3.4 H1:µ > 3.4 H1:p < 0.85 H1:p + 0.85 H1:p > 0.85 H1:µ < 3.4 %3D %3D The test is: right-tailed left-tailed two-tailed Based on a sample of 45 people, the sample mean GPA was 3.41 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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We want to test the claim, that the mean GPA of night student is significantly different than 3.4
Hence, null and alternative hypothesis is,
H0 : mu = 3.4 vs H1 : mu != 3.4
the alternative hypothesis is non-directional ie. Two -tailed.
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