g the claim μ1- μ2=0

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A: Given that, X-double bar=100 , s bar=8 n=4, α=0.0035 α2=0.00352=0.00175 z(α/2)=z(0.00175)=2.92…

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A: From the provided information,p* = 0.23E = 0.04Confidence level = 98%

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A: From the provided information, Degrees of freedom numerator = 5 Degrees of freedom denominator = 70…

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A: Given that   Proportion having genetic marker (p) = 18% = 0.18 Confidence level (C) = 90%  The…

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A: given data n1 =121p^1 = 0.75n2 = 100p^2 = 0.66H0 : p1 - p2 =0Ha : p1 - p2>0p value = ?

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A: Sample size n=302591

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A: Given that, Chi-square is equal to 22.30 X2= 22.30 and degrees of freedom is 15  Df= 15

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A:

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A: Where:

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A: Then we need to explain it.

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A:

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A: we have given that  two tailed test level of significance (α)=0.005

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A:

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A: Right Left D (D-dbar)^2 116 131 -15 46.24 112 143 -31 84.64 160 176 -16 33.64 200 191 9…

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A: a)Null and alternate hypothesis: C. H0:μ=11.0Ha:μ≠11.0

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A: