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The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C₂H5N306 (227.1 g/mol), is soluble in benzene, C6H6. How many grams of TNT are needed to generate an osmotic pressure of 4.95 atm when dissolved in 261 ml of a benzene solution at 298 K. grams TNT [Review Topics] [References] Use the References to access important values if needed for this question. Submit Answer Retry Entire Group 9 more group attempts remaining age Technical Support Previous Next> Save and Exit

The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C₂H5N306 (227.1 g/mol), is soluble in benzene, C6H6. How many grams of TNT are needed to generate an osmotic pressure of 4.95 atm when dissolved in 261 ml of a benzene solution at 298 K. grams TNT [Review Topics] [References] Use the References to access important values if needed for this question. Submit Answer Retry Entire Group 9 more group attempts remaining age Technical Support Previous Next> Save and Exit

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C₂H5N306 (227.1 g/mol), is soluble in benzene, C6H6. How many grams of TNT are needed to generate an osmotic pressure of 4.95 atm when dissolved in 261 ml of a benzene solution at 298 K. grams TNT [Review Topics] [References] Use the References to access important values if needed for this question. Submit Answer Retry Entire Group 9 more group attempts remaining age Technical Support Previous Next> Save and Exit
Transcribed Image Text:The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C₂H5N306 (227.1 g/mol), is soluble in benzene, C6H6. How many grams of TNT are needed to generate an osmotic pressure of 4.95 atm when dissolved in 261 ml of a benzene solution at 298 K. grams TNT [Review Topics] [References] Use the References to access important values if needed for this question. Submit Answer Retry Entire Group 9 more group attempts remaining age Technical Support Previous Next> Save and Exit
Expert Solution
Step 1

Given,

The nonvolatile, nonelectrolyte TNT (trinitrotoluene),C7H5N3O6 (227.1g/mol) , is soluble in benzene, C6H6 .

  An osmotic pressure of 4.95 atm when dissolved in 261 ml of a benzene solution at 298 K.

 Now , 

     The equation that will be used is:

                               π=i MRT

where:

i- Van't Hoff factor (1)

π- osmotic pressure (4.95 atm)

M- molar concentration (unknown)

T - temperature (298 K)

R- gas constant (0.0821 L.atm/mol.K) .

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