The net force on a current loop in a uniform magnetic field iszero. But what if B is not uniform? The figure (Figure 1)shows a square loop of wire that lies in the xy-plane. Theloop has corners at (0, 0), (0, L), (L, 0), and (L, L) andcarries a constant current I in the clockwise direction. Themagnetic field has no x-component but has both y- and z-components: B = (Boz/L) j+ (Boy/L) Ê, where Bo is apositive constant.Figure(0, L)y(0, 0)(L, L)(L, 0)1 of 1XPart FFind the direction of the force on side 1, that runs from (L, L) to (L, 0).OOOOO+x-direction-x-direction+y-direction-y-direction+z-direction-z-directionOSubmit Previous AnswersCorrect▼ Part GFind the magnitude of the force on side 4, that runs from (L, 0) to (0,0).Express your answer in terms of the variables Bo, L, and I.Π ΑΣΦF4 =Doarson****?

The magnetic field is B→=B0zL j^ + B0yLk^ where B0 is a positive constant. The current is flowing in…

The net force on a current loop in a uniform magnetic field is zero. But what if B is not uniform? The figure (Figure 1) shows a square loop of wire that lies in the xy-plane. The loop has corners at (0, 0), (0, L), (L, 0), and (L, L) and carries a constant current I in the clockwise direction. The magnetic field has no x-component but has both y- and z- components: B = (Boz/L) + (Boy/L) k, where Bo is a positive constant. Figure y (0, L) (0, 0) ½ (L, L) (L, 0) 1 of 1 X Part F Find the direction of the force on side 1, that runs from (L, L) to (L, 0). O +x-direction --direction O+y-direction -y-direction O+z-direction. 0 -z-direction 0 Submit Previous Answers ✓ Correct Part G Find the magnitude of the force on side 4, that runs from (L, 0) to (0, 0). Express your answer in terms of the variables Bo, L, and I. 195 ΑΣΦ ?

The net force on a current loop in a uniform magnetic field is zero. But what if B is not uniform? The figure (Figure 1) shows a square loop of wire that lies in the xy-plane. The loop has corners at (0, 0), (0, L), (L, 0), and (L, L) and carries a constant current I in the clockwise direction. The magnetic field has no x-component but has both y- and z- components: B = (Boz/L) + (Boy/L) k, where Bo is a positive constant. Figure y (0, L) (0, 0) ½ (L, L) (L, 0) 1 of 1 X Part F Find the direction of the force on side 1, that runs from (L, L) to (L, 0). O +x-direction --direction O+y-direction -y-direction O+z-direction. 0 -z-direction 0 Submit Previous Answers ✓ Correct Part G Find the magnitude of the force on side 4, that runs from (L, 0) to (0, 0). Express your answer in terms of the variables Bo, L, and I. 195 ΑΣΦ ?

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter13: Nuclear Structure

Section: Chapter Questions

Problem 2Q: A proton precesses with a frequency p in the presence of a magnetic field. If the intensity of the...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

100%

The net force on a current loop in a uniform magnetic field is
zero. But what if B is not uniform? The figure (Figure 1)
shows a square loop of wire that lies in the xy-plane. The
loop has corners at (0, 0), (0, L), (L, 0), and (L, L) and
carries a constant current I in the clockwise direction. The
magnetic field has no x-component but has both y- and z-
components: B = (Boz/L) j+ (Boy/L) Ê, where Bo is a
positive constant.
Figure
(0, L)
y
(0, 0)
(L, L)
(L, 0)
1 of 1
X
Part F
Find the direction of the force on side 1, that runs from (L, L) to (L, 0).
O
OOOO
+x-direction
-x-direction
+y-direction
-y-direction
+z-direction
-z-direction
O
Submit Previous Answers
Correct
▼ Part G
Find the magnitude of the force on side 4, that runs from (L, 0) to (0,0).
Express your answer in terms of the variables Bo, L, and I.
Π ΑΣΦ
F4 =
Doarson
****
?

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