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The movement of a thin metal diaphragm in a pressure guage is determined by the arrangement shown where the two electrodes E1 and E2 and the diaphragm D form two capacitors C1 and C2 in series. (Assume equilibrium distances E1 to D and E2 to D to be both equal to d, and the effective area of  C1 and C2 to be A.) Use the expression 1/V1 = (1/C1 + 1/C2)C1/V to show that when the diaphragm has been moved down a distance x from its central equilibrium position, V1 =  V(d + x)/ 2d

The movement of a thin metal diaphragm in a pressure guage is determined by the arrangement shown where the two electrodes E1 and E2 and the diaphragm D form two capacitors C1 and C2 in series. (Assume equilibrium distances E1 to D and E2 to D to be both equal to d, and the effective area of  C1 and C2 to be A.) Use the expression 1/V1 = (1/C1 + 1/C2)C1/V to show that when the diaphragm has been moved down a distance x from its central equilibrium position, V1 =  V(d + x)/ 2d

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The movement of a thin metal diaphragm in a pressure guage is determined by the arrangement shown where the two electrodes E1 and E2 and the diaphragm D form two capacitors C1 and C2 in series.

(Assume equilibrium distances E1 to D and E2 to D to be both equal to d, and the effective area of  C1 and C2 to be A.)

Use the expression 1/V1 = (1/C1 + 1/C2)C1/V to show that when the diaphragm has been moved down a distance x from its central equilibrium position, V1 =  V(d + x)/ 2d

 

V1 E1 C1 C2 V E2
Transcribed Image Text:V1 E1 C1 C2 V E2
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