The moment of inertia for a 2200 kg solid disc is 11800 kg-m². Find the radius of the disc.А.3.275 mD.3.893 mВ.3.932 mE.2.687 mС.2.951 mF.3.810 m

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The moment of inertia for a 2200 kg solid disc is 11800 kg-m². Find the radius of the disc. A. 3.275 m D. 3.893 m 3.932 m 2.951 m 2.687 m 3.810 m В. E. С. F.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 54A

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

The moment of inertia for a 2200 kg solid disc is 11800 kg-m². Find the radius of the disc.
А.
3.275 m
D.
3.893 m
В.
3.932 m
E.
2.687 m
С.
2.951 m
F.
3.810 m

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