Several children were playing on a merry-go-round at a playground. At this time, the merry-go-round (and children) had moment of inertia 170 kg-m? and rotational speed 4.1 rev/s. When two more children jumped onto the merry-go-round, the rotational speed dropped to 2.3 rev/s. What was the new moment of inertia? A. 266.2.kg-m2 B. 277.9 kg-m? C. 289.4 kg-m? 235.3.kg-m? F. D. E. 303 kg-m? 252.1 kg-m?
Several children were playing on a merry-go-round at a playground. At this time, the merry-go-round (and children) had moment of inertia 170 kg-m? and rotational speed 4.1 rev/s. When two more children jumped onto the merry-go-round, the rotational speed dropped to 2.3 rev/s. What was the new moment of inertia? A. 266.2.kg-m2 B. 277.9 kg-m? C. 289.4 kg-m? 235.3.kg-m? F. D. E. 303 kg-m? 252.1 kg-m?
College Physics
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
Transcribed Image Text:**Problem Description:**
Several children were playing on a merry-go-round at a playground. At this time, the merry-go-round (and children) had a moment of inertia of 170 kg·m² and a rotational speed of 4.1 rev/s. When two more children jumped onto the merry-go-round, the rotational speed dropped to 2.3 rev/s. What was the new moment of inertia?
---
**Options for the New Moment of Inertia (Iₓ):**
A. 266.2 kg·m²
B. 277.9 kg·m²
C. 303.1 kg·m²
D. 289.4 kg·m²
E. 235.3 kg·m²
F. 252.1 kg·m²
---
**Explanation:**
To find the new moment of inertia, use the conservation of angular momentum. The initial angular momentum (L₁) and final angular momentum (L₂) should be equal.
Initial angular momentum:
\( L₁ = I₁ \times \omega₁ \)
where \( I₁ = 170 \, \text{kg} \cdot \text{m}² \) and \( \omega₁ = 4.1 \, \text{rev/s} \).
Final angular momentum:
\( L₂ = I₂ \times \omega₂ \)
where \( \omega₂ = 2.3 \, \text{rev/s} \).
Equating L₁ and L₂:
\( I₁ \times \omega₁ = I₂ \times \omega₂ \)
Solve for \( I₂ \):
\( I₂ = \frac{I₁ \times \omega₁}{\omega₂} = \frac{170 \times 4.1}{2.3} \)
Calculate to find the correct answer from the options provided.
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