**Question 8:**A 1.6-kg ball of radius 25 cm rolls across level ground at 4.0 m/s without slipping. What is its angular velocity?**Options:**- 21 s⁻¹- 2.54 s⁻¹- 10.8 s⁻¹- 4.0 s⁻¹- 16 s⁻¹**Explanation:**To find the angular velocity (\(\omega\)) of the ball, use the relationship between linear velocity (\(v\)) and angular velocity:\[ \omega = \frac{v}{r} \]where:- \(v\) is the linear velocity (4.0 m/s),- \(r\) is the radius of the ball (0.25 m).Calculate \(\omega\) as follows:\[ \omega = \frac{4.0 \, \text{m/s}}{0.25 \, \text{m}} = 16 \, \text{s}^{-1} \]Thus, the angular velocity of the ball is \(16 \, \text{s}^{-1}\).

mass = 1.6 kg Radius = 25 cm = 0.25 m Speed = 4 m/s Using relation between linear and angular speed…

Answered: A 1.6-kg ball of radius 25 cm rolls…

A 1.6-kg ball of radius 25 cm rolls across level ground at 4.0 m/s without slipping. What is its angular velocity? 21 s-1 2.54 s-1 10.8 s-1 4.0 s-1 16 s-1

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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