A uniform disk of mass 2.31 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum? kg-m2/s

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Description:**

A uniform disk of mass 2.31 kg has a radius of 0.100 m and spins with a frequency of 0.550 revolutions per second. What is its angular momentum?

**Answer Box:**

\[ \boxed{\phantom{0}} \, \text{kg} \cdot \text{m}^2/\text{s} \]

**Explanation:**

To find the angular momentum \( L \) of the disk, use the formula: 

\[ L = I \cdot \omega \]

where \( I \) is the moment of inertia and \( \omega \) is the angular velocity in radians per second.

For a uniform disk, the moment of inertia \( I \) is given by:

\[ I = \frac{1}{2} m r^2 \]

where \( m = 2.31 \, \text{kg} \) is the mass of the disk and \( r = 0.100 \, \text{m} \) is the radius.

The angular velocity \( \omega \) in radians per second can be calculated from the frequency \( f = 0.550 \, \text{rev/s} \) using the conversion:

\[ \omega = 2\pi f \]

Substitute the given values into the equations to compute the angular momentum.
Transcribed Image Text:**Problem Description:** A uniform disk of mass 2.31 kg has a radius of 0.100 m and spins with a frequency of 0.550 revolutions per second. What is its angular momentum? **Answer Box:** \[ \boxed{\phantom{0}} \, \text{kg} \cdot \text{m}^2/\text{s} \] **Explanation:** To find the angular momentum \( L \) of the disk, use the formula: \[ L = I \cdot \omega \] where \( I \) is the moment of inertia and \( \omega \) is the angular velocity in radians per second. For a uniform disk, the moment of inertia \( I \) is given by: \[ I = \frac{1}{2} m r^2 \] where \( m = 2.31 \, \text{kg} \) is the mass of the disk and \( r = 0.100 \, \text{m} \) is the radius. The angular velocity \( \omega \) in radians per second can be calculated from the frequency \( f = 0.550 \, \text{rev/s} \) using the conversion: \[ \omega = 2\pi f \] Substitute the given values into the equations to compute the angular momentum.
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