The moist weight of 5.56 x 10 m³ of a soil is 120.3 x 10³ kN. The moisture content and the specific gravity of the soil solids are determined in the laboratory to be 10 % and 2.6, respectively. Calculate the following: a. Moist unit weight. (Enter your answer to three significant figures.) Y = kN/m³ b. Dry unit weight. (Enter your answer to three significant figures.) Yd= kN/m³ c. Void ratio. (Enter your answer to three significant figures.) e

The moist weight of 5.56 x 10 m³ of a soil is 120.3 x 10³ kN. The moisture content and the specific gravity of the soil solids are determined in the laboratory to be 10 % and 2.6, respectively. Calculate the following: a. Moist unit weight. (Enter your answer to three significant figures.) Y = kN/m³ b. Dry unit weight. (Enter your answer to three significant figures.) Yd= kN/m³ c. Void ratio. (Enter your answer to three significant figures.) e

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The Unit weight of a soil sample is 19. 6 Kilo-Newton per cubic meter. Calculate the following: a. Convert the unit in pcf (Pounds per cubic feet). b. Density in pcf (pounds per cubic feet). c. If the soil has a mass of 3 slugs, determine the volume of the soil in cubic feet. Show complete solution.
Number 11
Compute the total unit weight, dry unit weight, water content, and saturated unit weight of the soil sample below. Volume Weight Air Va Vv Vw Wa watef ww V Vs solids Ws Given: e = 0.8 s = 0.9 Gs = 2.68
Note: I need right solution with clear calculation.
12. Determine the specific gravity of soil solids based on the data below: Initial volume of soil in saturated state: 24.52 cm^3 Final volume of soil in dry state: 15.94 cm^3 Initial mass in saturated state: 44.71 g Final mass in saturated state: 30.10 g Round off to two decimal places.
1. An air dry (not oven dry) processed clay powder sample has the following measurements: - Mass of soil + tare (g) = 94.18 - Mass of oven dry soil + tare (g) = 93.50 - Mass of tare (g) = 30.18 - Volume of tare (cm³) = 139.17 Density of solids (kg/m³) = 2700 Determine: (a) water content, (b) total density, (c) total unit weight, (d) (oven) dry density, (e) (oven) dry unit weight, (f) void ratio, and (g) degree of saturation.
You've conducted a soil extraction on the site to have its soil profile determine, you've gathered the data has follows: Mass of the soil sample = 15 kilograms; Volume of the soil sample=0.007 cubic meter; Water content = 15%; Specific Gravity = 2.7. Determine the following: Void Ratio, Porosity, Saturation, Density of the Soil, Dry Density of the Soil, Unit weight of the soil, Dry Unit Weight of the soil, Saturated Unit Weight of the soil.
2. The moist weight of 5.56 × 10-3 m³ of a soil is 120.3 × 10-³ kN. The moisture content and the specific gravity of the soil solids are determined in the laboratory to be 10 % and 2.6, respectively. Calculate the following: a. Moist unit weight. (Enter your answer to three significant figures.) |kN/m³ b. Dry unit weight. (Enter your answer to three significant figures.) |kN/m³ c. Void ratio. (Enter your answer to three significant figures.) e = d. Porosity. (Enter your answer to three significant figures.) n = e. Degree of saturation. (Enter your answer to three significant figures.) S = |% f. Volume occupied by water. (Enter your answer to three significant figures.) Vu = dm³
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SITUATION 3 A sample of clay soil of volume 1/1000 cubic meter and mass of 1.762 kg, after being dried out in an oven had a mass of 1.368 kg. The specific gravity of the particles was 2.69. Calculate the void ratio. Your answer Find the volume of air in the original sample. Your answer Determine the density of sample of soil when completely saturated, assuming that it has the same void ratio. Your answer
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A SOIL SAMPLE WAS TAKEN FROM A SITE AND WAS PLACED IN A CUBICAL CONTAINER WITH ONE SIDE EQUAL TO 0.1m. THE NET WEIGHT OF THE SOIL IS FOUND OUT TO BE 2kN. AFTER OVEN DRYING, THE WEIGHT WAS REDUCED TO 53%. WHAT IS THE UNIT WEIGHT OF THE SOIL AFTER DRYING? * Your answer