The medical researcher is comparing two treatments for lowering cholesterol: diet and meds. The researcher wants to see if the patients who receive the recommendation to change their diet have more success lowering cholesterol compared to a prescription of meds. A random sample of some patients who received the recommendation to change their diet and others who were prescribed meds was taken. The results of how many did or did not lower their cholesterol are shown below: Data on Diet vs. Meds for Weight Loss Diet Meds Yes 424 502 No 255 320 What can be concluded at the = 0.05 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for the difference between two dependent population means t-test for a population mean z-test for the difference between two population proportions t-test for the difference between two independent population means The null and alternative hypotheses would be: Select an answer μ1 p1 Select an answer ≠ < = > Select an answer p2 μ2 (please enter a decimal) Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > Based on this, we should Select an answer fail to reject reject accept the null hypothesis. using a Ti84 with steps
The medical researcher is comparing two treatments for lowering cholesterol: diet and meds. The researcher wants to see if the patients who receive the recommendation to change their diet have more success lowering cholesterol compared to a prescription of meds. A random sample of some patients who received the recommendation to change their diet and others who were prescribed meds was taken. The results of how many did or did not lower their cholesterol are shown below:
Data on Diet vs. Meds for Weight Loss
| Diet | Meds | |
|---|---|---|
| Yes | 424 | 502 |
| No | 255 | 320 |
What can be concluded at the = 0.05 level of significance?
For this study, we should use Select an answer z-test for a population proportion t-test for the difference between two dependent population means t-test for a population mean z-test for the difference between two population proportions t-test for the difference between two independent population means
- The null and alternative hypotheses would be:
Select an answer μ1 p1 Select an answer ≠ < = > Select an answer p2 μ2 (please enter a decimal)
Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (Please enter a decimal)
- The test statistic ? t z = (please show your answer to 3 decimal places.)
- The p-value = (Please show your answer to 4 decimal places.)
- The p-value is ? ≤ >
- Based on this, we should Select an answer fail to reject reject accept the null hypothesis.
using a Ti84 with steps
It is appropriate to compare proportion of of individuals on diet and meds who had lost weight. So it is appropriate to use a z-test to compare the population proportion of individuals who lost weight under diet and medicines.
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