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The mean score of a competency test is 82, with a standard deviation of 2. Between what two values do about 99.7% of the values lie? (Assume the data set has a bell-shaped distribution) O A. Between 76 and 88 O B. Between 80 and 84 O C. Between 78 and 86 O D. Between 74 and 90

The mean score of a competency test is 82, with a standard deviation of 2. Between what two values do about 99.7% of the values lie? (Assume the data set has a bell-shaped distribution) O A. Between 76 and 88 O B. Between 80 and 84 O C. Between 78 and 86 O D. Between 74 and 90

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The mean score of a competency test is 82, with a standard deviation of 2. Between what two values do about 99.7% of the values lie? (Assume the data set has a bell-shaped distribution.) - A. Between 76 and 88 - B. Between 80 and 84 - C. Between 78 and 86 - D. Between 74 and 90 [Answer: Use the empirical rule for normal distributions, which states that approximately 99.7% of data within a normal distribution lies within three standard deviations of the mean. Calculate the range: Mean ± 3(Standard Deviations). Here, it is 82 ± 3(2) = 76 to 88, which corresponds to option A.] **Additional Options:** - View Instructor Tip - Calculator (**Note:** Illustration of options on screen to engage students in solving statistical probability questions.)
Transcribed Image Text:The mean score of a competency test is 82, with a standard deviation of 2. Between what two values do about 99.7% of the values lie? (Assume the data set has a bell-shaped distribution.) - A. Between 76 and 88 - B. Between 80 and 84 - C. Between 78 and 86 - D. Between 74 and 90 [Answer: Use the empirical rule for normal distributions, which states that approximately 99.7% of data within a normal distribution lies within three standard deviations of the mean. Calculate the range: Mean ± 3(Standard Deviations). Here, it is 82 ± 3(2) = 76 to 88, which corresponds to option A.] **Additional Options:** - View Instructor Tip - Calculator (**Note:** Illustration of options on screen to engage students in solving statistical probability questions.)
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