Please answer this for me. Åge(ans)891011121314151617181900Filles Garçons(secondes)0,50,470,50,460,480,440,460,420,440,390,420,380,430,390,420,390,410,380,420,370,390,380,350,45Quintique Canada, Recer 1.Determines in a table, the average, median andstandard deviation of each of the distributions to avariable (age, girl reaction time and boys reactiontime).What interpretations can you make of it?A.) For each of the three two-variable distributions,make a graphical representation using atechnological tool and calculate the values that canbe used to interpret them.B.) Interpret graphic representations and drawconclusions.

From the given information: Age Girl reaction time Boy reaction time 8 5 47 9 5 46 10 48 44…

Answered: 1.Determines in a table, the average,…

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Author:Amos Gilat

Publisher:Amos Gilat

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Question

Please answer this for me.

Åge
(ans)
8
9
10
11
12
13
14
15
16
17
18
19
00
Filles Garçons
(secondes)
0,5
0,47
0,5
0,46
0,48
0,44
0,46
0,42
0,44
0,39
0,42
0,38
0,43
0,39
0,42
0,39
0,41
0,38
0,42
0,37
0,39
0,38
0,35
0,45
Quintique Canada, Recer

1.Determines in a table, the average, median and
standard deviation of each of the distributions to a
variable (age, girl reaction time and boys reaction
time).What interpretations can you make of it?
A.) For each of the three two-variable distributions,
make a graphical representation using a
technological tool and calculate the values that can
be used to interpret them.
B.) Interpret graphic representations and draw
conclusions.

Expert Solution

Step 1

From the given information:

Age	Girl reaction time	Boy reaction time
8	5	47
9	5	46
10	48	44
11	46	42
12	44	39
13	42	38
14	43	39
15	42	39
16	41	38
17	42	37
18	39	38
19	35	45

Age:

Let X=Age,

	X	${(X - \bar{X})}^{2}$
	8	30.25
	9	20.25
	10	12.25
	11	6.25
	12	2.25
	13	0.25
	14	0.25
	15	2.25
	16	6.25
	17	12.25
	18	20.25
	19	30.25
Sum	162	$\sum_{} {(X - \bar{X})}^{2} = 143$
	$\bar{X} = \frac{s u m}{n} = \frac{162}{12} = 13.5$	$s \tan d a r d d e v i a t i o n = \sqrt{\frac{\sum_{} {(X - \bar{X})}^{2}}{n - 1}} = \sqrt{\frac{143}{12 - 1}} = 3.606$

Median:

Arrange the X values in ascending order:

8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19

Here, n=12, which is even number.

$M e d i a n = \frac{\frac{n}{2} t h t e r m + (\frac{n}{2} + 1) t h t e r m}{2} = \frac{6 t h t e r m + 7 t h t e r m}{2} = \frac{13 + 14}{2} = 13.5$