The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows: –13.625 0.375 –0.625 12.375 –2.625 –3.625 2.375 5.375 If this is sample data, the sample variance is and the sample standard deviation is . If this is population data, the population variance is and the population standard deviation is . Suppose the smallest value of 80 in the data was misrecorded as 8. If you were to recalculate the variance and standard deviation with the 8 instead of the 80, your new values for the variance and standard deviation would be .
The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows: –13.625 0.375 –0.625 12.375 –2.625 –3.625 2.375 5.375 If this is sample data, the sample variance is and the sample standard deviation is . If this is population data, the population variance is and the population standard deviation is . Suppose the smallest value of 80 in the data was misrecorded as 8. If you were to recalculate the variance and standard deviation with the 8 instead of the 80, your new values for the variance and standard deviation would be .
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows:
–13.625 | 0.375 | –0.625 | 12.375 | –2.625 | –3.625 | 2.375 | 5.375 |
If this is sample data, the sample variance is and the sample standard deviation is .
If this is population data, the population variance is and the population standard deviation is .
Suppose the smallest value of 80 in the data was misrecorded as 8. If you were to recalculate the variance and standard deviation with the 8 instead of the 80, your new values for the variance and standard deviation would be .
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