The mean of the difference data (attached) is x bar = 8.95 with a standard deviation SD = 23.88. 1. Find a 99% confidence interval for the mean difference (scented –unscented) in improvement in completion times. 2. Provide an interpretation of this interval in the context of possible extra improvement with floral scent.
The mean of the difference data (attached) is x bar = 8.95 with a standard deviation SD = 23.88. 1. Find a 99% confidence interval for the mean difference (scented –unscented) in improvement in completion times. 2. Provide an interpretation of this interval in the context of possible extra improvement with floral scent.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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1. Find a 99% confidence interval for the mean difference (scented –unscented) in improvement in completion times.
2. Provide an interpretation of this interval in the context of possible extra improvement with floral scent.

Transcribed Image Text:ScentTest
% Unscented % Scented
33.07
43.13
9.31
-3.66
28.41
42.86
15.26
30.65
21.86
16.42
7.37
16.37
20.44
3.17
-23.43
27.06
-3.35
27.25
32.78
-0.17
22.77
37.3
-6.77
35.89
19.64
22.14
28.69
7.85
9.05
-19.08
11.06
43.12
17.48
29.16
-10.23
-26.72
15.43
38.52
-22.51
12.44
-4.62
26.04
Expert Solution

Step 1
(1)
The degrees of freedom is,
The critical-value is obtained by using Excel function “=TINV(probability, degrees of freedom)”.
Output obtained from Excel is given below:
From the output, the t* is 2.977.
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