The mean number of hours of sleep that a college student gets per night is 6 hours with a standard deviation of 3 hours. A random sample of forty students is observed. It is of interest to determine the probability that a single student gets less than 5 hours of sleep at night. Identify the correct formula for solving. O P(X < 5) = P (Z < ) (6-5) P(X < 5) = P (Z < P (X < 5) = P (z < (5-6) O P(X < 5) = P (z < "„) (5-6) P (X < 5) = P (z < ) P(X < 3) = P (z < ) (6-5) (5-6) V40 P (X < 5) = P (2 < ) (5-6) None of the above /Unable to solve

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) = P ( Z < )
The mean number of hours of sleep that a college student gets per night is 6 hours with a standard deviation of 3 hours. A random sample of forty
students is observed. It is of interest to determine the probability that a single student gets less than 5 hours of sleep at night. Identify the correct
formula for solving.
P (X < 5) = P ( 2
(6–5)
Z <
3
®,")
O P(X <5) = P ( Z <
(5–6)
3
(5–6)
P (X < 5) = P ( Z <
3
V40
P(X < 5) = P ( Z < ®,")
O P(X < 5) = P(z < ")
(5-6)
9
(6–5)
3
V40
P (X < 5) = P ( Z <
(5–6)
9.
V40
(5–6)
P (X < 5) = P (Z
V40
O None of the above / Unable to solve
Transcribed Image Text:) = P ( Z < ) The mean number of hours of sleep that a college student gets per night is 6 hours with a standard deviation of 3 hours. A random sample of forty students is observed. It is of interest to determine the probability that a single student gets less than 5 hours of sleep at night. Identify the correct formula for solving. P (X < 5) = P ( 2 (6–5) Z < 3 ®,") O P(X <5) = P ( Z < (5–6) 3 (5–6) P (X < 5) = P ( Z < 3 V40 P(X < 5) = P ( Z < ®,") O P(X < 5) = P(z < ") (5-6) 9 (6–5) 3 V40 P (X < 5) = P ( Z < (5–6) 9. V40 (5–6) P (X < 5) = P (Z V40 O None of the above / Unable to solve
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