**Educational Website Text** Scores for a common standardized college aptitude test are normally distributed with a mean (\(\mu\)) of 505 and a standard deviation (\(\sigma\)) of 95. Randomly selected people are given a Test Preparation Course before taking this test. For the purposes of this example, assume the course has no effect on their scores. **Problem 1: Probability of Individual Score** If 1 person is randomly selected, find the probability that their score is at least 536.3. \[ P(X > 536.3) = 329 \times \] (Note: The value seems incorrect as it suggests a probability greater than 1.) **Problem 2: Probability of Mean Score for a Sample** If 18 people are randomly selected, find the probability that their mean score is at least 536.3. \[ P(M > 536.3) = 1.40 \times \] (Note: The value here is also incorrect, as probabilities cannot exceed 1.) In both problems, a red "×" is shown next to the probability calculations, indicating that the provided answers are incorrect. Graph/Diagram Explanation: The image does not contain graphs or diagrams.
**Educational Website Text** Scores for a common standardized college aptitude test are normally distributed with a mean (\(\mu\)) of 505 and a standard deviation (\(\sigma\)) of 95. Randomly selected people are given a Test Preparation Course before taking this test. For the purposes of this example, assume the course has no effect on their scores. **Problem 1: Probability of Individual Score** If 1 person is randomly selected, find the probability that their score is at least 536.3. \[ P(X > 536.3) = 329 \times \] (Note: The value seems incorrect as it suggests a probability greater than 1.) **Problem 2: Probability of Mean Score for a Sample** If 18 people are randomly selected, find the probability that their mean score is at least 536.3. \[ P(M > 536.3) = 1.40 \times \] (Note: The value here is also incorrect, as probabilities cannot exceed 1.) In both problems, a red "×" is shown next to the probability calculations, indicating that the provided answers are incorrect. Graph/Diagram Explanation: The image does not contain graphs or diagrams.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Educational Website Text**
Scores for a common standardized college aptitude test are normally distributed with a mean (\(\mu\)) of 505 and a standard deviation (\(\sigma\)) of 95. Randomly selected people are given a Test Preparation Course before taking this test. For the purposes of this example, assume the course has no effect on their scores.
**Problem 1: Probability of Individual Score**
If 1 person is randomly selected, find the probability that their score is at least 536.3.
\[ P(X > 536.3) = 329 \times \]
(Note: The value seems incorrect as it suggests a probability greater than 1.)
**Problem 2: Probability of Mean Score for a Sample**
If 18 people are randomly selected, find the probability that their mean score is at least 536.3.
\[ P(M > 536.3) = 1.40 \times \]
(Note: The value here is also incorrect, as probabilities cannot exceed 1.)
In both problems, a red "×" is shown next to the probability calculations, indicating that the provided answers are incorrect.
Graph/Diagram Explanation: The image does not contain graphs or diagrams.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa25edf9-6d5d-4338-a85f-2d06afad4f74%2F4bd15f6d-f538-427d-9d17-078cd423ab71%2Fdldpvgg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Website Text**
Scores for a common standardized college aptitude test are normally distributed with a mean (\(\mu\)) of 505 and a standard deviation (\(\sigma\)) of 95. Randomly selected people are given a Test Preparation Course before taking this test. For the purposes of this example, assume the course has no effect on their scores.
**Problem 1: Probability of Individual Score**
If 1 person is randomly selected, find the probability that their score is at least 536.3.
\[ P(X > 536.3) = 329 \times \]
(Note: The value seems incorrect as it suggests a probability greater than 1.)
**Problem 2: Probability of Mean Score for a Sample**
If 18 people are randomly selected, find the probability that their mean score is at least 536.3.
\[ P(M > 536.3) = 1.40 \times \]
(Note: The value here is also incorrect, as probabilities cannot exceed 1.)
In both problems, a red "×" is shown next to the probability calculations, indicating that the provided answers are incorrect.
Graph/Diagram Explanation: The image does not contain graphs or diagrams.
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