Scores for a common standardized college aptitude test are normally distributed with a mean of μ = 505 and a standard deviation of a = 95. Randomly selected people are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the test has no effect. If 1 of the people is randomly selected, find the probability that their score is at least 536.3. P(X> 536.3) 329 If 18 of the people are randomly selected, find the probability that their mean score is at least 536.3. P(M 536.3) -

MATLAB: An Introduction with Applications
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Scores for a common standardized college aptitude test are normally distributed with a mean of μ = 505
and a standard deviation of a = 95. Randomly selected people are given a Test Preparation Course before
taking this test. Assume, for sake of argument, that the test has no effect.
If 1 of the people is randomly selected, find the probability that their score is at least 536.3.
P(X> 536.3) 329
If 18 of the people are randomly selected, find the probability that their mean score is at least 536.3.
P(M
536.3) -
Transcribed Image Text:Scores for a common standardized college aptitude test are normally distributed with a mean of μ = 505 and a standard deviation of a = 95. Randomly selected people are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the test has no effect. If 1 of the people is randomly selected, find the probability that their score is at least 536.3. P(X> 536.3) 329 If 18 of the people are randomly selected, find the probability that their mean score is at least 536.3. P(M 536.3) -
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