The mean height of the 281 adult females in the Budenoside group is 163 cm, and the sample standard deviationis 10 cm. Which of the following is true about the sample standard deviation ?If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting samplestandard deviation of these 500 values would be larger than 10 cm.95% of the sample values for any sample of data are always within +/- 2 sample standard deviations from thesample mean.This is the variability in the 281 individual heights for the 281 adult females in this Budenoside sample.If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting samplestandard deviation of these 500 values would be smaller than 10 cm. A 2012 article in the New England Journal reports the results of a randomized trial to assess the association betweenregular usage of asthma medication prior to turning 18 years old, and height at age 18 years. As per the authors,"From December 1993 through September 1995,we randomly assigned 1041 children between the ages of 5 and 13 yearswith mild-to-moderate asthma to one of three study groups in the double-blind, placebo-controlled CAMP trial."(reference: Kelly H, et al. Effect of Inhaled Glucocorticoids in Childhood on Adult Height. New England of Medicine (2012).367 (10))The random assignment groups were Budesonide, Nedocromil and placebo. The following graphic shows the distributionof female and male participant heights at different times in the study follow-up, presented for the Budesonide andplacebo samples.A Unadjusted Height Distribution200-BudesonidePlacebo190-180-170-160-150-140-130-120-110-100-0-Trial entry2 YrTrial endAdultTrial entry2 YrTrial endAdultFemalesMalesHeight (cm)

Empirical rule: The empirical rule is in a statisitc known as 68% - 95% - 99.7% rule. That meas,…

The mean height of the 281 adult females in the Budenoside group is 163 cm, and the sample standard deviation is 10 cm. Which of the following is true about the sample standard deviation ? If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting sample standard deviation of these 500 values would be larger than 10 cm. 95% of the sample values for any sample of data are always within +/- 2 sample standard deviations from the sample mean. This is the variability in the 281 individual heights for the 281 adult females in this Budenoside sample. If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting sample standard deviation of these 500 values would be smaller than 10 cm.

The mean height of the 281 adult females in the Budenoside group is 163 cm, and the sample standard deviation is 10 cm. Which of the following is true about the sample standard deviation ? If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting sample standard deviation of these 500 values would be larger than 10 cm. 95% of the sample values for any sample of data are always within +/- 2 sample standard deviations from the sample mean. This is the variability in the 281 individual heights for the 281 adult females in this Budenoside sample. If the researchers had randomized 500 women to receive Budenoside, instead of 281 women, the resulting sample standard deviation of these 500 values would be smaller than 10 cm.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

What is the standard deviation of a sample of 120 observations, if the variance of the sample 2.56?
Suppose a researcher wants to test if the average diastolic blood pressure in Irish-Americans is different than the average diastolic blood pressure in the general population. Note that the average diastolic blood pressure in the general population is 70 mmHG. The researcher recruits 30 Irish-Americans into this particular study and then measures each of their diastolic blood pressures (mmHG). The population of this sample has a standard deviation equal to 3.0. What is the two-sided alternative hypothesis? (in words) Group of answer choices The mean is different than 70 The mean is different than 73 The mean is greater than 70 The mean is greater than 73
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
You have obtained the number of years of education from one random sample of 38 police officers from City A and the number of years of education from a second random sample of 30 police officers from City B. The average years of education for the sample from City A is 15 years with a standard deviation of 2 years. The average years of education for the sample from City B is 14 years with a standard deviation of 2.5 years. Is there a statistically significant difference between the education levels of police officers in City A and City B?What is the appropriate test for this case? 2 sample z-testChi-square test 2-sample t-test2 sample paired t-test Carry out the test. The test statistic = (round answer to two decimal places.)and the p-value is (round answer to 2 decimal places)There sufficient evidence at the 5% level to conclude that the education levels of police officers in City A and City B is significantly different.
The human resources department of a consulting firm gives a standard creativity test to a randomly selected group of new hires every year. This year, 100 new hires took the test and scored a mean of 113.6 points with a standard deviation of 134. Last year, 95 new hires took the test and scored a mean of 116.4 points with a standard deviation of 16.8. Assume that the population standard deviations of the test scores of all new hires in the current year and the test socores of all new hires last year can be estimated by the sample standard deviations, as the samples used were quite large. Construct a 90 confidence interval for the difference between the mean test score , of new hires from the current year and the mean test score , of new hires from last year. Then tind the lower limit and upper limit of the 905% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answeis to at least two decimal places. (If necessary, cosult a list.ot…
a distribution with a mean of u=41 and a standard deviation of 4 is transformed into a standardized distribution with a mean of u=100 and a standardized deviation =20, find the new standardized score for each of the following values from the original population, x=39, x=36, x=45, x=50
In a school district, all sixth grade students take the same standardized test. The superintendant of the school district takes a random sample of 3030 scores from all of the students who took the test. She sees that the mean score is 169169 with a standard deviation of 7.06747.0674. The superintendant wants to know if the standard deviation has changed this year. Previously, the population standard deviation was 1313. Is there evidence that the standard deviation of test scores has decreased at the α=0.005α=0.005 level? Assume the population is normally distributed. Step 1 of 5: State the null and alternative hypotheses. Round to four decimal places when necessary. Step 2 of 5: Determine the critical value(s) of the test statistic. If the test is two-tailed, separate the values with a comma. Round your answer to three decimal places. Step 3 of 5: Determine the value of the test statistic. Round your answer to three decimal places. Step 4 of 5: Make the…
The brain volumes (cm³) of 20 brains have a mean of 1113.7 cm³ and a standard deviation of 128.9 cm³. Use the give standard deviation and the range rule of thumb to identify the limits separating values that are significantly low or significantly high. For such data, would a brain volume of 1361.5 cm³ be significantly high? 3 Significantly low values are cm³ or lower. (Type an integer or a decimal. Do not round.)
Assume that weights of adult females are normally distributed with a mean of 77 kg and a standard deviation of 22 kg. What percentage of individual adult females have weights between 71 kg and 83 kg? If samples of 100 adult females are randomly selected and the mean weight is computed for each sample, what percentage of the sample means are between 71 kg and 83 kg?
Q1. For the giving dataset (X) below, calculate the following X= (455.2, 676.7, 784.7, 349.1, 437.5, 678.3, 760.2, 788.4, 278.3 and 455.2} 1) The Range ( 2) The Mode 3) The variance ( ).
In a random sample of 6 cell phones, the mean full retail price was 517.30 and standard deviation is 184.00. Further research suggests that the population mean is 425.73. Does the t-value for the original sample fall between -t0.99 and t0.99?
The human resources department of a consulting firm gives a standard creativity test to a randomly selected group of new hires every year. This year, 65 new hires took the test and scored a mean of 113.2 points with a standard deviation of 13.4. Last year, 100 new hires took the test and scored a mean of 116.8 standard deviation of 14.6. Assume that the population standard deviations of the test scores of all new hires in the current year and the test scores of all new hires last year can be estimated by the sample standard deviations, as the samples used were quite large. Construct a 95% confidence interval points with for 4-, the difference between the mean test score u, of new hires from the current year and the mean test score , of new hires from last year. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary, consult a list of…