The mean height of 15-year-old boys (in cm) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are normally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys will exceed the mean height of the sample of girls by 1 or more is: 0.9938 O 0.9878 O 0.0062 0.9972

The mean height of 15-year-old boys (in cm) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are normally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys will exceed the mean height of the sample of girls by 1 or more is: 0.9938 O 0.9878 O 0.0062 0.9972

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The mean height of 15-year-old boys (in em) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are nomally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys would be higher than the mean height of the sample of girls 18: O 0 9878 O 0.0062 O 0.9938 0 9972 Let E[X(Y-1)] 10, E[X(Y#1)] 20, V(X) Then E(Y) 8. V(Y) 12 and V(X+Y) 30. O 14/5 12/5 2